Answer:
contain equal numbers of particles. ... MELTING POINT is the temperature at which a solid turns into liquid. ... Determine the energy required (in Joules) when the temperature of 3.21 grams of water increases by 4.0 °C ... Solve for at mater RW 100. ... How much heat energy is released when 12.8 g of barium oxide react with
Explanation:
Magnetism is a non contact force. This is brcause magnetism “acts on an object without being in physical contact with it”
Answer: 0.887 g of
should be added to excess HCl(aq).
Explanation:
According to ideal gas equation:

P = pressure of gas = 805 torr = 1.06 atm (760torr=1atm)
V = Volume of gas = 235 ml = 0.235 L
n = number of moles = ?
R = gas constant =
T =temperature =



According to stoichiometry:
1 mole of chlorine is produced by = 1 mole of 
Thus 0.0102 moles of chlorine is produced by =
moles of 
Mass of
=
0.887 g of
should be added to excess HCl(aq).
8 H2= 0.90 g , hope that helps
you with your work