The molecular formula for sodium chloride is NaCl. The sum of their atomic weights is (22.99 grams/mole + 35.45 grams/mole) = 58.44 grams/mole
take (17.0 grams)/(58.44 grams/mole), which equals 0.291 moles of NaCl.
D = m / V
13.6 = 8.3 / V
V = 8.3 / 13.6
V = 0.610 mL
hope this helps!
Titration is the method used.
D) All three bulbs would go out because the circuit would no longer have a ground thereby deeming it "open".
