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2 years ago

What happens to the function f(x)=x2 when it becomes f′(x)=x2−3?

Mathematics

1 answer:

yanalaym [24]2 years ago

7 0

Answer:

c) it moves 3 units downwards

Step-by-step explanation:

f'(x) = f(x) - 3

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3 + root 3 *2 +root 2

icang [17]

Answer:

6 + 3 $\sqrt{2}$ + 2 $\sqrt{3}$ + $\sqrt{6}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

(3 + $\sqrt{3}$ )(2 + $\sqrt{2}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

3(2 + $\sqrt{2}$ ) + $\sqrt{3}$ (2 + $\sqrt{2}$ ) ← distribute both parenthesis

= 6 + 3 $\sqrt{2}$ + 2 $\sqrt{3}$ + $\sqrt{6}$

4 0

2 years ago

Anyone know how to do parts of complex numbers

Agata [3.3K]

Answer:

Re = 6.2

Im = 37

Step-by-step explanation:

Re is the Real Axis which is the real number in the equation (6.2).

Im is the Imaginary Axis which is the imaginary number in the equation (37)

6 0

2 years ago

I don't understand this.

sladkih [1.3K]

You mean the word or number

7 0

3 years ago

Step 3: Now multiply the values to get 14,918,904,000. That is almost 15 billion passwords.

Troyanec [42]

The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600

<h3>How to determine the number of passwords</h3>

The given parameters are:

Password length = 8

Letters = 6

Numbers = 2

There are 26 letters and 10 digits.

Since the letters and the numbers can be repeated, then the number of passwords is:

Count = 26^6 * 10^2

Evaluate

Count = 30891577600

Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600