All categories

3 years ago

If a vehicle is moving at 45m/s initially 36m/s after 2.0s and 27m/s after 4.0s at what time will it come to a stop

Physics

1 answer:

lyudmila [28]3 years ago

8 0

Answer:

a1 = (v2 - v1) / t1 = (36 - 45) m/s / 2 s = -4.5 m/s^2

a2 = (v3 - v2) / t2 = (27 - 36) m/s / 2 s = -4.5 m / s^2

So the vehicle is apparently uniformly decelerating at -4.5 m/s^2

t = (vf - vi) / a = (0 - 45) m/s / -4.5 m/s^2 = 10 sec

You might be interested in

Which of the following represents a case in which you are not accelerating? -Driving 60 miles per hour around a curve -Going fro

PIT_PIT [208]

Answer:

Driving in a straight line at 60 miles per hour

Explanation:

In the first case there's an acceleration that modifies the direction of the movement.

In the second case there's a lineal acceleration that increases the speed of the car.

in the third case there's a negative acceleration that reduces the speed of the car.

On the third case the speed is constant so the acceleration is 0 mi/s^2

8 0

3 years ago

A stone is dropped from the upper observation deck of a tower, "500" m above the ground. (Assume g = 9.8 m/s2.) (a) Find the dis

Yuri [45]

Answer:

h₍₁₎ = 495,1 meters

h₍₂₎ = 480,4 m

h₍₃₎ = 455,9 m

...

Explanation:

The exercise is "free fall". t = $\sqrt{\frac{2h}{g} }$

Solving with this formula you find the time it takes for the stone to reach the ground (T) = 102,04 s

The heights (h) according to his time (t) are found according to the formula:

h(t) = 500 - 1/2 * g * t²

Remplacing "t" with the desired time.

4 0

3 years ago

The ice skaters partner liftes her up a distance of 1 m work done or not work done

SOVA2 [1]

Answer:

Work done.

Explanation:

The skater who lifts has to overcome the partner's weight. When lifted up by 1 meter, her potential energy increases by (mass)x(gravitational acceleration)x(1meter), which is the amount of work done.

(This all assumes lifting vertically and no other forces being part of the picture)

5 0

2 years ago

Two ions with masses of 4.39×10−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic field is

Ilia_Sergeevich [38]

Answer:

7.2 cm

Explanation:

magnetic field, B = 0.301 T

speed, v = 7.92 x 10^5 m/s

mass, m = 4.39 x 10^-27 kg

q = 1.6 x 10^-19 C

The radius of singly changed ion is given by

$r = \frac{mv}{Bq}$

where, m is the mass of ion, v be the speed of ion, B is the magnetic field and q be the charge

$r = \frac{4.39\times 10^{-27}\times 7.92 \times 10^{5}}{0.301\times 1.6\times 10^{-19}}$

r = 0.072 m

r = 7.2 cm

5 0

3 years ago

Pairs of magnets are shown in the diagram.

belka [17]

The answer is X. I hope this helped

8 0

3 years ago

Read 2 more answers