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3 years ago

If a vehicle is moving at 45m/s initially 36m/s after 2.0s and 27m/s after 4.0s at what time will it come to a stop

Physics

1 answer:

lyudmila [28]3 years ago

8 0

Answer:

a1 = (v2 - v1) / t1 = (36 - 45) m/s / 2 s = -4.5 m/s^2

a2 = (v3 - v2) / t2 = (27 - 36) m/s / 2 s = -4.5 m / s^2

So the vehicle is apparently uniformly decelerating at -4.5 m/s^2

t = (vf - vi) / a = (0 - 45) m/s / -4.5 m/s^2 = 10 sec

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ZanzabumX [31]

Answer:

$\theta=32rad$

Explanation:

In an uniformly accelerated circular motion, the angle traveled by the object is given by:

$\theta=\frac{\omega_f+\omega_0}{2}t$

Here $\omega_f$ is the final angular speed, $\omega_0$ is the initial angular speed and t is the time of the motion. Replacing the given values:

$\theta=\frac{12\frac{rad}{s}+4\frac{rad}{s}}{2}(4s)\\\theta=32rad$

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3 years ago

The formula can be used to convert temperatures between degrees Fahrenheit () and degrees Celsius (). How many degrees are in th

Jlenok [28]

Answer:

-30°C

Explanation:

F-32/180 =C-0/100

or, -22-32/180=C/100

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or, -0.3*100=C

therefore, C= -30

-22°F = -30°C

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2 years ago

Explain briefly how solar energy is used to generate electricity

valkas [14]

Answer:

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Explanation:

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2 years ago

What’s an example of contact friction

kotegsom [21]

Answer:

a nightstand on a lamp table

Explanation:

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3 years ago

Pe=___

Nesterboy [21]

Answer:

H = start height (v = 0)

h = present height

v = present speed

assuming no friction

total energy = PE + KE

mgH = mgh + .5mv^2

if PE = KE then

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Explanation:

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3 years ago