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4 years ago

What is the final electron receptor in the light reaction of photosynthesis?

Physics

1 answer:

Mumz [18]4 years ago

7 0

Answer: Nicotinamide adenine dinucleotide phosphate (NADP)

Explanation:

<u>Photosynthesis</u> is a metabolic process in which light is transformed into stable chemical energy, converting inorganic matter into organic matter.

This process is mainly divided in two parts:

-Light-dependent reactions (also called light reactions)

-Light-independent reactions (also called dark reactions).

In the case of light reactions, the light is used by the plant to produce organic energy molecules, being the coenzyme Nicotinamide adenine dinucleotide phosphate (NADP) the final electron acceptor.

It should be noted, this coenzyme is also involved in the dark phase of photosynthesis, in which carbon dioxide ( $CO_{2}$ ) is fixed into carbohydrates.

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A rigid container holds 0.30g of hydrogen gas.

Strike441 [17]

Answer:

Part A: $\mathbf{Q =94 \ J}$ to two significant figures

Part B: $\mathbf{Q =160 \ J}$ to two significant figures

Part C: $\mathbf{Q =220 \ J}$ to two significant figures

Explanation:

Given that :

mass of the hydrogen = 0.30 g

the molar mass of hydrogen gas molecule = 2 g/mol

we all know that:

number of moles = mass/molar mass

number of moles = 0.30 g /2 g/mol

number of moles = 0.15 mol

For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = $C_v=\dfrac{3}{2}R$

For Part A:

$Q = mC_v\Delta T$

$Q= 0.15 \ mol (\dfrac{3}{2})(8.314 \ J/mole.K )(100-50)K$

$Q= 0.15 \times (\dfrac{3}{2}) \times (8.314 \ J )\times (50)$

$Q=93.5325 \ J$

$\mathbf{Q =94 \ J}$ to two significant figures

Part B. For hot temperature, $C_v=\dfrac{5}{2}R$

$Q = mC_v\Delta T$

$Q= 0.15 \ mol (\dfrac{5}{2})(8.314 \ J/mole.K )(300-250)K$

$Q= 0.15 \times (\dfrac{5}{2}) \times (8.314 \ J )\times (50)$

$Q=155.8875 \ J$

$\mathbf{Q =160 \ J}$ to two significant figures

Part C. For an extremely hot temperature, $C_v=\dfrac{7}{2}R$

$Q = mC_v\Delta T$

$Q= 0.15 \ mol (\dfrac{7}{2})(8.314 \ J/mole.K )(2300-2250)K$

$Q= 0.15 \times (\dfrac{7}{2}) \times (8.314 \ J )\times (50)$

$Q=218.2425 \ J$

$\mathbf{Q =220 \ J}$ to two significant figures

6 0

3 years ago

A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process have protons been add

AlladinOne [14]

Answer: A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process electrons been removed from it.

Explanation:

It is known that for every atom the protons and neutrons reside in the nucleus of the atom. Whereas electrons move outside the nucleus of an atom. As a result, electrons are able to transfer more easily from one substance to another as compared to the protons.

This is because protons are tightly held by the nucleus of an atom. Whereas electrons are mobile in nature and hence, they can easily move.

Therefore, positive charge on the glass develops due to the removal of electrons from it.

thus, we can conclude that in the given process electrons been removed from the glass object.

8 0

3 years ago

A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 4.0 cm from the axis of rotation. (a) Calcul

Annette [7]

Answer:

a) a = 0.477 m/s^2

b) u = 0.04862

Explanation:

Given:-

- The rotational speed of the turntable N = 33 rev/min

- The watermelon seed is r = 4.0 cm away from axis of rotation.

Find:-

(a) Calculate the acceleration of the seed, assuming that it does not slip. (b) What is the minimum value of the coefficient of static friction between the seed and the turntable if the seed is not to slip

Solution:-

- First determine the angular speed (w) of the turntable.

w = 2π*N / 60

w = 2π*33 / 60

w = 3.456 rad/s

- The watermelon seed undergoes a centripetal acceleration ( α ) defined by:

α = w^2 * r

α = 3.456^2 * 0.04

α = 0.477 m / s^2

- The minimum friction force (Ff) is proportional to the contact force of the seed.

- The weight (W) of the seed with mass m acts downwards. The contact force (N) can be determined from static condition of seed in vertical direction.

N - W = 0

N = W = m*g

- The friction force of the (Ff) is directed towards the center of axis of rotation, while the centripetal force acts in opposite direction. The frictional force Ff = u*N = u*m*g must be enough to match the centripetal force exerted by the turntable on the seed.

Ff = m*a

u*m*g = m*a

u = a / g

u = 0.477 / 9.81

u = 0.04862

8 0

3 years ago

If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate it

Bogdan [553]

Answer:

5m/s²

Explanation:

Initial Velocity= 40m/s

Final Velocity=60m/s

Time = 4s

a=(v-u)/t

a=60-40/4

a=20/4

a=5m/s²

8 0

3 years ago

When a cyclist moves downhill without pedalling, what type of energy does he gain?

Vesna [10]

Answer:

He is gaining kinetic energy and losing potential energy

Explanation:

3 0

2 years ago

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