An object in projectile motion will follow which path?

A 100 kilowatt bulb burns for 3 hours how much energy did it use

belka [17]

Answer:

1.08×10⁹ J

Explanation:

From the question given above, the following data were obtained:

Power (P) = 100 kilowatt

Time (t) = 3 hours

Energy (E) =?

Next, we shall convert 100 kilowatt to Watts. This can be obtained as follow:

1 KW = 1000 W

Therefore,

100 KW = 100 KW × 1000 W / 1 KW

100 KW = 100000 W

Thus, 100 KW is equivalent to 100000 W.

Next, we shall convert 3 hrs to second (s). This can be obtained as follow:

1 h = 3600 s

Therefore,

3 h = 3 h × 3600 s / 1 h

3 h = 10800 s

Thus, 3 h is equivalent to 10800 s.

Finally, we shall determine the amount of energy consumed as follow:

Power (P) = 100000 W

Time (t) = 10800 s

Energy (E) =?

P = E/t

100000 = E / 10800

Cross multiply

E = 100000 × 10800

E = 1.08×10⁹ J

Therefore, 1.08×10⁹ J of energy was consumed.

4 0

3 years ago

If a girl running along a straight road with a uniform velocity 1.5m/s,find her acceleration

Eddi Din [679]

Her acceleration is zero, because her velocity is not changing.

6 0

3 years ago

What is the average speed of an object that travels 50 meters in 2 seconds? Select one: a. 100 m/s b. 25 m/s c. 50 m/s d. 2 m/s

AURORKA [14]

Answer:

Average speed, v = 25 m/s

Explanation:

It is given that,

Distance travelled by the object, d = 50 meters

Time taken, t = 2 seconds

Average speed is defined as the total distance divided by total time taken i.e.

$v=\dfrac{d}{t}$

$v=\dfrac{50\ m}{2\ s}$

v = 25 m/s

So, the sped of the object is 25 m/s. Hence, this is the required solution.

8 0

3 years ago

If an object moving at 5 m/s accelerates for 30 seconds at a rate of 2

klasskru [66]

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

4 0

3 years ago

A paintball’s mass is 0.0032kg. A typical paintball strikes a target moving at 85.3 m/s.

vekshin1

Answer:

A) If the paintball stops completely the magnitude of the change in the paintball’s momentum is $p=0.273kg*m/s$

B) If the paintball bounces off its target and afterward moves in the opposite direction with the same speed, the change in the paintball’s momentum is $p=0.546kg*m/s$

C) A paintball bouncing off your skin in the opposite direction with the same speed hurts more than a paintball exploding upon your skin because of the strength exerted is twice than if it explodes.

Explanation:

Hi

A) We use the formula of momentum $p=mv$ , so we have $p=0.0032kg*85.3m/s=0.273kg*m/s$

B) We use the same formula above, then due we have a change of direction at the same speed, therefore the change in the momentum is the double so

$p=2*0.0032kg*85.3m/s=0.546kg*m/s$ .

C) The average strength of the force an object exerts during impact is determined by the amount the object’s momentum changes. therefore

$F=\frac{\Delta p}{\Delta t}$ , as we don't have any data about the impact time but we know momentum is twice, time does no matter and strength is twice too.

4 0

4 years ago