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2 years ago

An object in projectile motion will follow which path?

Physics

1 answer:

Tanzania [10]2 years ago

6 0

It will look like an upside down parabola

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A puck of mass m 0.085 kg is going in a circle on a horizontal frictionless surface. It is held in its orbit by massless string

attashe74 [19]

Answer:

Explanation:

Magnitude of tension

= centripetal force

= m ω²R

= m (2π/T)² R , T is time period of revolution.

= .085 x (2 x 3.14 / .55)² x .84

= 9.3 N .

8 0

3 years ago

What effect does an u balanced force have on an object?

Free_Kalibri [48]

Effect of balanced force'
*net force is zero
*no change in shape
*no change in size
*equal and opposite force

6 0

3 years ago

select the example that best describes a renewable resource. a. all the houses built in the new neighborhood had natural gas ava

Bad White [126]

B. my town is powered by electricity that is generated by the energy from the flow of water through a large dam.

The water from the large dam is example of renewable energy. It can be replenished through rainfall cycle, so it is a renewable form of energy.

4 0

3 years ago

Read 2 more answers

Is the movement of wind kinetic energy ?

kari74 [83]

Answer: Well that is a good question and the answer is that wind energy is motion which is kinetic energy since its a renewable energy source.

Hope it helps

3 0

4 years ago

A ship sailing in the Gulf Stream is heading 25.0º west of north at a speed of 4.00 m/s relative to the water. Its velocity rela

ASHA 777 [7]

Answer:

Velocity of Gulf Stream= $34.5^\circ$ west of north at a speed of $2.03\ \rm m/s$

Explanation:

Given

speed of ship relative to Gulf stream= $25^\circ$ west of north at a speed of 4 m/s

speed of ship relative to earth= $5^\circ$ west of north at a speed of 4 .8 m/s

Let $V_S$ be the velocity of the ship relative to the earth and $V_{sg}$ be the velocity of the ship with respect to the Gulf stream

Let the west direction be negative x axis and north direction be positive x axis

Now

$V_{sg}=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\V_s-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\-4.8\sin5^\circ \vec i+4.8\cos5^\circ \vec j-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\Vg=-1.68\vec\ i+1.156\vec\ j\ \rm m/s\\$

magnitude of the velocity is given by

$V_g=\sqrt{(1.68^2+1.156^2)}\\V_g=2.03\ \rm m/s\\$

Let the velocity of gulf stream makes an angle $\theta$ with the positive y axis we have

$\tan\theta=\dfrac{1.156}{1.68}\\\theta=34.5^\circ$

Velocity of Gulf Stream $34.5^\circ$ west of north at a speed of $2.03\ \rm m/s$

8 0

3 years ago