Alpha particle has a mass of 4 (Two protons and two neutrons)
Neutron has a mass of 1
Beta particle has a mass of about 0 (Electron)
Proton has a mass of 1
So the answer is (2) Beta particle
The –OH+ group is most acidic proton in ln-OH as shown in figure (a). The proton is circled in the figure.
The stabilisation of the conjugate base produced is stabilises due to resonance factor. The possible resonance structures are shown in figure (b).
The acidity of a protonated molecule depends upon the stabilisation of the conjugate base produced upon deprotonation. The conjugate base of ln-OH is shown in figure (a).
The possible resonance structures are shown in figure (b). As the number of resonance structures of the conjugate base increases the stabilisation increases. Here the unstable quinoid (unstable) form get benzenoid (highly stable) form due to the resonance which make the conjugate base highly stabilise.
Thus the most acidic proton is assigned in ln-OH and the stability of the conjugate base is explained.
Answer is: XeF₄.
p₁ (F₂) = 8,0 atm.
p₁ (Xe) = 1,7 atm.
p₂ (F₂) = 4,6 atm.
p₂ (Xe) = 0 atm, all reacted.
p - partial pressure.
pressure of F₂ reacted = Δp (F₂) = 8.0 - 4.6 = 3.4 atm.
pressure of Xe reacted = Δp(Xe) = 1,7 - 0 = 1,7 atm.
Δp (F₂) / Δp(Xe) = 3,4 atm / 1,7 atm = 2:1.
Reaction: 2F₂ + Xe → XeF₄ (xenon-tetrafluoride)
<h2>d=density, m=mass, v=volume</h2>
1. 17.2kg=17200g
so knowing that d=m/V, use V=m/d to calculate the volume
v=17200/5.75
and then devide by 1000 to convert cm3 to dm3 and the answer will be in dm3
2. d=m/v
v=0.5l
m=425g
so use the formula and you will get d=425/0.5=850g/l
3. use d=m/v again, but not before rewriting the formula for volume: m=vd and convert dm3 to cm3
1dm3=1000cm3
so 0.987dm3 =987 cm3
now m=987cm3 * 10.5g/cm3 and the answer will be in grams
The periodic table was invented by Russian chemist Dmitri Mendeleev in 1869.