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Nikolay [14]
3 years ago
14

Write an equation of the line below.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0

(5,2)

(1,1)

hope its help you

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Step-by-step explanation:

3 0
3 years ago
Solve on the interval [0/2pi]<br><br> 1-cos(theta) = (1/2)
Airida [17]

Answer:

Final answer is x=\frac{\pi}{3} and x=\frac{5\pi}{3}.

Step-by-step explanation:

Given equation is 1-\cos\left(\theta\right)=\frac{1}{2}

Now we need to find the solution of  1-\cos\left(\theta\right)=\frac{1}{2} in given interval [0, 2\pi ].

1-\cos\left(\theta\right)=\frac{1}{2}

-\cos\left(\theta\right)=\frac{1}{2}-1

-\cos\left(\theta\right)=-\frac{1}{2}

\cos\left(\theta\right)=\frac{1}{2}

which gives x=\frac{\pi}{3} and x=\frac{5\pi}{3} in the given interval.

Hence final answer is x=\frac{\pi}{3} and x=\frac{5\pi}{3}.

6 0
3 years ago
write an equation for a line that is parallel to line that passes through the points (5,5),(-1,3) and contains the point (-6,-8)
dimaraw [331]
Since the two lines are parallel then they have the same slope which = 1/3

since the line passes through (-6 , -8)

y+8 = (1/3)(x+6)

3y + 24 = x + 6

x - 3y = 18 is the equation
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3 years ago
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