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Nikolay [14]
3 years ago
14

Write an equation of the line below.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0

(5,2)

(1,1)

hope its help you

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A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
Pls hurry Solve the application problem. Find the area of a counter top that measures 2 yards by 2/5 yard.
sergiy2304 [10]

Answer:

I believe its C i saw this yesterday somewhere not 100% sure

Step-by-step explanation:

4 0
1 year ago
What is the probability of landing on a yellow or blue and red section when given two spins?
Vanyuwa [196]
100 is the best answer
3 0
3 years ago
I NEED HELP VOLUME OF SPHERES 5 QUESTIONS ASAP!!!!
Alexeev081 [22]

Answer:

1.)4188.79

2.) 7238.23

3.)1.02

4.)4189

5.)170 cm³

Step-by-step explanation:

1.) 4πr2 * 5

2.) 4πr2 * 12

3.) V = 4/3(PI*r3). *4.5

4.) V = 4/3 π r ^3 * 10

5.) Given:

Cylindrical container: height = 18 cm ; diameter = 6 cm.

3 balls each have a radius of 3 cm.

Volume of a cylinder = π r² h

V = 3.14 * (3cm)² * 18 cm

V = 508.68 cm³

Volume of rubber ball = 4/3  π r³

V = 4/3 * 3.14 * (3cm)³

V = 113.04 cm³

113.04 cm³  * 3 balls = 339.12 cm³

508.68 cm³ - 339.12 cm³ = 169.56 cm³ or 170 cm³

There is 170 cm³ free space in the container.

6 0
3 years ago
Square root of (-16)^2
katen-ka-za [31]

Answer: \sqrt{(-16)^{2} } =16

Step-by-step explanation:

I looked it up on my calculator. I hope this helps!! :)

5 0
2 years ago
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