Answer:
Vx = 35 x cos(13deg)
Vy = 35 x sin(13deg) - gt
(g is acceleration due to gravity =~9.8 meter/second^2, t is time in second)
Explanation:
The tiger leaps up, then x and y component of its velocity are:
Vx = Vo x cos(alpha)
Vy = Vo x sin(alpha) - gt
(Vo is tiger's initial velocity, alpha is angle between its leaping direction and horizontal plane)
Hope this helps!
The gravitational force between the objects A. It would increase.
Explanation:
The magnitude of the gravitational force between two objects is given by:
where
G is the gravitational constant
are the masses of the two objects
r is the separation between the objects
In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of 
increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.
Therefore, the correct answer is
A. It would increase.
Learn more about gravitational force:
brainly.com/question/1724648
brainly.com/question/12785992
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Boyle's law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4l , the pressure is 720 kpa (kilopascals). What is the pressure when the volume is 10l ?
Answer: 3.48g
Explanation:
here, we will be using conservation of momentum to solve the problem. i.e the total momentum remains unchanged, unless an external force acts on the system. We'll in thus question, there is no external force acting in the system.
Remember, momentum = mass * velocity, then
mass of blood * velocity of blood = combined mass of subject and pallet * velocity of subject and pallet
Velocity of blood = 56.5cm = 0.565m
mass of blood * 0.565 = 54kg * (0.000063/0.160)
mass of blood * 0.565 = 54 * 0.00039375
mass of blood * 0.565 = 0.001969
mass of blood = 0.00348kg
Thus, the mass of blood that leaves the heart is 3.48g
Answer:
Option e) 320 s
Explanation:
Here, distance = 3.0 km = 3000 m
The velocity of boat when it is going upstream;
Upstream velocity = velocity of boat in still water - velocity of river flow
So, Upstream velocity 
So,Time to go upstream
The velocity of boat when it is going downstream;
Downstream velocity = velocity of boat in still water + velocity of river flow
So, Downstream velocity 
So,Time to go downstream
So, total time (t) = 
Option E is the correct answer.
