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lyudmila [28]
2 years ago
6

How many atoms are in a sample of 0.75 moles of carbon atoms

Chemistry
2 answers:
vova2212 [387]2 years ago
8 0

Answer: 4.5165 *10^-23 moles Carbon

Explanation:

There are 6.022*10^23 atoms in a mole.

Therefore, there would be 6.022*10^-23*0.75 atoms in 0.75 moles of Carbon.

= 4.5165 *10^-23 moles Carbon

ryzh [129]2 years ago
3 0

Answer: 4.5165 *10^-23 moles Carbon

Explanation:

There are 6.022*10^23 atoms in a mole.

Therefore, there would be 6.022*10^-23*0.75 atoms in 0.75 moles of Carbon.

= 4.5165 *10^-23 moles Carbon

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120mph

Explanation:

Google

divide the speed value by 1.467

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176 times 60 second in a minute times 60 minutes in an hour

than divide by 5280 the amount of feet in a mile

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2 years ago
What is the pressure of 5.0 mol nitrogen (N2) gas in a 2.0 L container at 268
CaHeK987 [17]

Answer: 54.94atm

Explanation: Please see attachment for explanation

8 0
3 years ago
How is oxygen different than neon explain your answer
lora16 [44]
Oxygen and neon are both elements. Oxygen has 8 electrons and 8 protons. Neon has 10 electrons and 10 protons. Oxygen is also a non-metal element and Neon is a noble gas.
5 0
3 years ago
How many moles of gas occupy 98L at a pressure of 2.8atm and a temperature of 292k? and what law would you use?
algol13
Let's assume that the gas has ideal gas behavior.

Then we can use ideal gas equation,
PV = nRT

Where, P is Pressure of the gas (Pa), V is volume of the gas (m³), n is the number of moles of gas (mol), R is the Universal gas constant (8.314 J mol⁻¹ K⁻¹) and T is the temperature in Kelvin (K)

The given data for the gas is,
P = 2.8 atm = 283710 Pa
V = 98 L = 98 x 10⁻³ m³
T = 292 K
R = 8.314 J mol⁻¹ K⁻¹
n = ?

By applying the formula,
283710 Pa x 98 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 292 K
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Hence,moles of gas is 11.45 mol.
8 0
3 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

8 0
3 years ago
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