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lyudmila [28]
2 years ago
6

How many atoms are in a sample of 0.75 moles of carbon atoms

Chemistry
2 answers:
vova2212 [387]2 years ago
8 0

Answer: 4.5165 *10^-23 moles Carbon

Explanation:

There are 6.022*10^23 atoms in a mole.

Therefore, there would be 6.022*10^-23*0.75 atoms in 0.75 moles of Carbon.

= 4.5165 *10^-23 moles Carbon

ryzh [129]2 years ago
3 0

Answer: 4.5165 *10^-23 moles Carbon

Explanation:

There are 6.022*10^23 atoms in a mole.

Therefore, there would be 6.022*10^-23*0.75 atoms in 0.75 moles of Carbon.

= 4.5165 *10^-23 moles Carbon

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Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


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3 years ago
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so it needs 1 electron to stabilise

that's why 1 covalent bond

hope it helps!!

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