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zubka84 [21]
2 years ago
7

Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained

an insoluble impurity?.
Chemistry
1 answer:
Delicious77 [7]2 years ago
3 0

Answer:

higher

Explanation:

If it contains a impurity that is insoluble it won't dissolve completely, the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

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How to balance CH4 + O2=CO2+H2O
sertanlavr [38]

Answer:

LHS-RHS

1 C - 1 C

4 H-2 H

2 O- 3 O

So on right side 2 hydrogen are less and one oxygen is more..so

Balanced equation is

CH4+2O2==CO2 + 2H2O

Explanation:

7 0
3 years ago
Read 2 more answers
What is the mole fraction of acetic acid in a solution containing 2 moles of vinegar and 3 moles of water? A. 2 B. 3 C. 0.4 D. 0
9966 [12]

Answer:

C. 0.4.

Explanation:

<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>

<em></em>

- no. of moles of acetic acid = 2, no. of moles of water = 3.

- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.

<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>

3 0
3 years ago
Read 2 more answers
Covalent bonding involves the sharing of electrons to create a full valence shell, and
Leno4ka [110]
True. Covalent bonds involve sharing electrons to create a full valence shell.
8 0
2 years ago
Read 2 more answers
What is the molarity of a solution containing 8.9 g of NaOH in 550. mL of NaOH solution?
bulgar [2K]

Answer:

0.4 M

Explanation:

Molarity is defined as moles of solute, which in your case is sodium hydroxide,  

NaOH

, divided by liters of solution.

molarity

=

moles of solute

liters of solution

Notice that the problem provides you with the volume of the solution, but that the volume is expressed in milliliters,  

mL

.

Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to

determine how many moles of sodium hydroxide you have in that many grams

convert the volume of the solution from milliliters to liters

So, to get the number of moles of solute, use sodium hydroxide's molar mass, which tells you what the mass of one mole of sodium hydroxide is.

7

g

⋅

1 mole NaOH

40.0

g

=

0.175 moles NaOH

The volume of the solution in liters will be

500

mL

⋅

1 L

1000

mL

=

0.5 L

Therefore, the molarity of the solution will be

c

=

n

V

c

=

0.175 moles

0.5 L

=

0.35 M

Rounded to one sig fig, the answer will be

c

=

0.4 M

Explanation:

6 0
2 years ago
How many grams of iron(II) chloride are needed to produce 44.3 g iron(II) phosphate in the presence of excess sodium phosphate?
zalisa [80]

Answer:

47.2 g

Explanation:

Let's consider the following double displacement reaction.

3 FeCl₂ + 2 Na₃PO₄ → Fe₃(PO₄)₂ + 6 NaCl

The molar mass of Fe₃(PO₄)₂ is 357.48 g/mol. The moles corresponding to 44.3 g are:

44.3 g × (1 mol / 357.48 g) = 0.124 mol

The molar ratio of Fe₃(PO₄)₂ to FeCl₂ is 1:3. The moles of FeCl₂ are:

3 × 0.124 mol = 0.372 mol

The molar mass of FeCl₂ is 126.75 g/mol. The mass of FeCl₂ is:

0.372 mol × (126.75 g/mol) = 47.2 g

5 0
3 years ago
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