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zubka84 [21]
2 years ago
7

Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained

an insoluble impurity?.
Chemistry
1 answer:
Delicious77 [7]2 years ago
3 0

Answer:

higher

Explanation:

If it contains a impurity that is insoluble it won't dissolve completely, the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

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Answer:

6.5 liters​.

Explanation:

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n is the no. of moles of the gas in mol.

R  is the general gas constant,

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<em></em>

  • Knowing that:

V₁  = 4.5 L, n₁ = 0.80 mol,

V₂  =  ??? L, n₂ = 0.35 + 0.80 = 1.15 mol.

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<em>(V₁n₂) = (V₂n₁)</em>

<em></em>

<em>∴ V₂ = (V₁n₂)/n₁ </em>= (4.5 L)(1.15 mol)/(0.8 mol) = <em>6.469 L ≅ 6.5 L.</em>

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<em>So, the right choice is: 6.5 liters​.</em>

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