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zloy xaker [14]
2 years ago
11

How do I determine the number of atoms in 30.0 g of K

Chemistry
1 answer:
Alika [10]2 years ago
8 0

The number of atoms in 30.0 g of K would be 4.632  x 10^{23} atoms.

<h3>Avogadro's number</h3>

1 mole of a substance contains 6.022 x 10^{23} atoms.

Mole of 30.0 g of K potassium = 30/39

                                                       = 0.7692 moles

Hence, 0.7692 moles of K would contain

                     0.7692 x 6.022 x  10^{23} atoms.

                                = 4.632  x 10^{23} atoms.

More on Avogadro's number can be found here: brainly.com/question/1445383

                   

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