How do I determine the number of atoms in 30.0 g of K

Chemistry

1 answer:

Alika [10]2 years ago

8 0

The number of atoms in 30.0 g of K would be 4.632 x $10^{23}$ atoms.

<h3>Avogadro's number</h3>

1 mole of a substance contains 6.022 x $10^{23}$ atoms.

Mole of 30.0 g of K potassium = 30/39

= 0.7692 moles

Hence, 0.7692 moles of K would contain

0.7692 x 6.022 x $10^{23}$ atoms.

= 4.632 x $10^{23}$ atoms.

More on Avogadro's number can be found here: brainly.com/question/1445383

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