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ss7ja [257]
3 years ago
12

a net force f accelerates a mass m with an acceleration a. if the same net force is applied to mass 5m, then the acceleration wi

ll be
Physics
1 answer:
diamong [38]3 years ago
3 0

Answer:

F=ma

a =F/m

a =F/5m ms-2,,,,,

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Where is the energy in a glucose molecule stored?
Semmy [17]

Answer:

Energy is stored in the bonds between atoms

4 0
3 years ago
Which of the following best describes a substance in which the temperature remains constant while at the same time it is experie
katen-ka-za [31]

Answer:

The right option is (d) substance undergoing a change of state

Explanation:

Latent Heat: Latent heat is the heat required to change the state of a substance without change in temperature. Latent heat is also known as hidden heat because the heat is not visible. The unit is Joules (J).

Latent heat is divided into two:

⇒ Latent Heat of fusion

⇒ Latent Heat of vaporization.

Latent Heat of fusion: This is the heat  energy required to convert a substance from its solid form to its liquid form without change in temperature. E.g (Ice) When ice is heated, its temperature rise steadily until a certain temperature is reached when the solid begins to melts.

Latent Heat of vaporization: This is the heat required to change a liquid substance to vapor without a change in temperature. The latent heat depend on the mass of the liquid and the nature of the liquid. E.g When water is heated from a known temperature  its boiling point (100°C) When more heat is supplied to its boiling temperature, it continue to boil without a change in temperature.

From The above, Latent heat brings about  a change of state of a substance at a steady temperature.

The right option is (d) substance undergoing a change of state

4 0
4 years ago
Sam heaves a 16lb shot straight upward, giving it a constant upward acceleration from rest of 35 m/s^2 for 64.0 cm. He releases
makvit [3.9K]

Answer:

6.69 m/s

4.483 m

1.42s

Explanation:

Given that:

Initial Velocity, u = 0

Final velocity, v =?

Acceleration, a = 35m/s²

1.) using the relation :

v² = u² + 2as

v² = 0 + 2(35) * 64*10^-2m

v² = 70 * 0.64

v = sqrt(44.8)

v = 6.693

v = 6.69 m/s

B.) height from the ground, h0 = 2.2

How high ball went , h:

Using :

v² = u² + 2as

Upward motion, g = - ve

0 = 6.69² + 2(-9.8)*(h - 2.2)

0= 6.69² - 19.6(h - 2.2)

44.7561 + 43.12 - 19.6h = 0

19.6h = 44.7561 - 43.12

h = 87.8761 / 19.6

h = 4.483 m

C.)

vt - 0.5gt² = h - h0

6.69t - 0.5(9.8)t²

6.69t - 4.9t² = 1.83 - 2.2

-4.9t² + 6.69t + 0.37 = 0

Using the quadratic equation solver :

Taking the positive root:

1.4185 = 1.42s

5 0
3 years ago
A 44.6 kg ice skater is moving at 5.14 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.
hodyreva [135]
This question is asking the force on the rope. We can find this by using centripetal acceleration, then multiply by the ice skater's mass.

First we need to find the centripetal acceleration, which is a = v^2/r

We are given v and r, so we solve for a.

a = [(5.14m/s)^2]/(0.525m) = 50.323 m/s^2

Next multiply by the ice skater's mass (because F=ma) which is 44.6 kg

We then get F = (50.323m/s^2)(44.6kg) = 2244.407924N

Divide by 10^3 to get kN, we get:

2.244kN

Hope this helps!
6 0
3 years ago
A uniform cylindrical steel wire (density: 7.8 x 103 kg/m3), 58.0 cm long and 1.34 mm in diameter, is fixed at both ends. To wha
lbvjy [14]

Answer:

T= 354.65 N

Explanation:

Given that

ρ= 7800 kg/m³

L= 58 cm

d=1.34 mm

f= 311 Hz

T= Tension

Speed of wave ,V

V = f λ      

V = f L

V= 311 x 0.58 m/s

V=180.38 m/s

Area of cross sectional

A= πr² mm²

A= 3.14 x 0.67² mm²

A=1.41 mm²

Mass = Density x Volume

m=7800\times 1.41\times 10^{-6}\ kg/m

m=0.0109 kg/m

Tension ,T

T=m V^2

T= 0.0109 x 180.38² N

T= 354.65 N

     

3 0
4 years ago
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