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Zielflug [23.3K]
3 years ago
8

How to calculate motion​

Physics
2 answers:
BlackZzzverrR [31]3 years ago
8 0

Answer:

Newton's second law, which states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration a of its centre of mass, F = ma, is the basic equation of motion in classical mechanics.

Explanation:

otez555 [7]3 years ago
3 0

Answer:

Distnace per unit time

Explanation:

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Explain how gravity and friction work to slow down a kicked soccer ball.
goblinko [34]
Use your feet to stop it since it is soccer you can't use your hands!!!! P.S. you can't use gravity.

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3 years ago
Blank is a measure of the percentage of water vapor in the air in a particular area
zaharov [31]

Answer:

Relative humidity is a measure of the percentage of water vapor in the air in a particular area

4 0
3 years ago
A nearsighted person cannot see objects further away than 10 m clearly. This person wants to be able to see objects 300 m away w
icang [17]

Answer:

d.-10.3m

Explanation:

Note for short sightedness the focal length is negative

Let do be object distance=10m

And di= image distance=-300m

Using lens formula

F=do*di/do-di= 10*300/10-300=-10.3m

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3 years ago
Read 2 more answers
What is the name of the part of the wave that is labeled -
tresset_1 [31]

Answer:

amplitude

Explanation:

sound travel and it amplifies

7 0
3 years ago
An ideal gas is brought through an isothermal compression process. The 3.00 mol 3.00 mol of gas goes from an initial volume of 2
ozzi

Answer:

The answers can be found by considering the isothermal expansion equation as well as the ideal gas equation from where we have

The temperature T = 602.64K and the final pressure P = 110.24MPa

Explanation:

Numbeer of moles of gas = 3.00 mol  

initial volume = 230.8×10−6 m3  

final volume = 133.4×10−6 m3 .

released energy =  8240 J

Temperature = Constant = T

Pressure =  p_{f} =unknown

From the relation the combined ideal gas law, PV = nRT

Where R = 8.314 4621.JK−1mol−1

we have The release energy from compression P1V1 -P2V2

-qrev = -nRTln(\frac{V_{2} }{V_{1} }) = 8240J

n = 3

Hence -nRTln(\frac{V_{2} }{V_{1} }) =  3×8.314 462×ln(\frac{133.4}{230.8}) × T=  -8240 J

or -13.67×T = -8240J, thus T = -8240/-13.67 = 602.64K

The Final pressure is given by

PV = n×R×T from where we have V = final volume thus

P = (n×R×T)/V = (3×8.134×602.64)÷(133.4×10^{-6}) = 110237041.1 N/m^{2} = 110.237MPa

8 0
3 years ago
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