Answer:
-5 V
Explanation:
The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value
vb−va
is negative.
We can calculate the potential difference between the two points by using the law of conservation of energy:

where:
is the change in kinetic energy of the particle
is the charge of the particle
is the potential difference
Re-arranging the equation, we can find the value of the potential difference:

Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
= 
where :


comparing the general form with the given equation
= 18.2329

hence the short period oscillation frequency (
) = 0.063 rad/sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Answer:
10 N
Explanation:
F = ma = m(Δv/t) = 5.0(10.0 - 0)/5.0 = 10 N