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Serhud [2]
3 years ago
14

¿como representarían la expresión "cualquier posición"?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

How would you represent the expression "any position"?

Step-by-step explanation:

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A man purchased 100 shares of a company’s stock at $3 per share. If each share rose $0.09 in value during the first month, decre
Neporo4naja [7]
$310 dollars because after it res and decreased it gained $.10 and 100 x 3 is 300 so thats before you calculate how much it rose so .10 x 100 is 10 so add that to 300 and you get 310
6 0
3 years ago
Solve for x : log(3x) + log(x + 4) = log(15).<br><br>Please explain it to me.​
zlopas [31]

Answer:

x = 1

Explanation:

\sf \rightarrow log(3x) + log(x + 4) = log(15)

Rule: log(a) + log(b) = log(ab)

\sf \rightarrow log(3x(x + 4)) =  log(15)

cancel out log on both sides

\sf \rightarrow 3x(x + 4) = 15

relocate constant variable

\sf \rightarrow 3x^2 + 12x -15 = 0

take 3 as a common factor

\sf \rightarrow 3(x^2 + 4x -5) = 0

divide both sides by 3

\sf \rightarrow x^2 + 4x -5 = 0

middle term split

\sf \rightarrow x^2 + 5x -x-5 = 0

factor common terms

\sf \rightarrow x(x  + 5) -1(x+5)= 0

collect into groups

\sf \rightarrow (x-1)(x+5)= 0

set to zero

\sf \rightarrow x-1 = 0 , \ x+5= 0

relocate variables

\sf \rightarrow x = 1,  \ x = -5

There must be a positive solution for log, so the solution is only x = 1

3 0
2 years ago
Read 2 more answers
Do the opposite quantities combine to make 0? Mark Yes or No for each.
amid [387]
1. yes
2. no
3. no
4. yes
4 0
2 years ago
Solve quadratic formulax^2-4x+3=0
bekas [8.4K]

The general formula for a equation of the form:

ax^2+bx+c=0

is:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}

then:

x_1=\frac{4+2}{2}=\frac{6}{2}=3

and

x_2=\frac{4-2}{2}=\frac{2}{2}=1

Therefore, x=3 or x=1.

8 0
1 year ago
Find an equation of the line(-2,-9) and(-7,-3)
andriy [413]

Answer:

The required equation is 6x+5y+57=0.

3 0
3 years ago
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