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1 year ago

Which of the following is NOT true about the exothermic reaction?

1 answer:

Natasha2012 [34]1 year ago

7 0

The statement that is not true about the exothermic reaction is that the potential energy of the product is higher than the potential energy of the reactant. That is option D.

<h3>What is an exothermic reaction?</h3>

An exothermic reaction is the reaction that releases heat to the environment which causes increase in the immediate environment.

The characteristics of exothermic reaction include the following:

Activation energy of the forward reaction is smaller than the activation energy of the reverse reaction.

Heat is released to the environment during reaction.

Since there is release of heat, the product will have a lower energy than the reactant.

Therefore, the statement that is not true about the exothermic reaction is that the potential energy of the product is higher than the potential energy of the reactant.

Learn more about exothermic reaction here:

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mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and $pK_{a}$ is as follows.

pH = $pK_{a} + log \frac{base}{acid}$

where, pH = 7.4 and $pK_{a}$ = 7.21

As here, we can use the $pK_{a}$ nearest to the desired pH.

So, 7.4 = 7.21 + $log \frac{base}{acid}$

0.19 = $log \frac{base}{acid}$

$\frac{base}{acid}$ = 1.55

1 mM phosphate buffer means $[HPO_{4}]$ + $[H_{2}PO_{4}]$ = 1 mM

Therefore, the two equations will be as follows.

$\frac{HPO_{4}}{H_{2}PO_{4}}$ = 1.55 ............. (1)

$[HPO_{4}]$ + $[H_{2}PO_{4}]$ = 1 mM ........... (2)

Now, putting the value of $[HPO_{4}]$ from equation (1) into equation (2) as follows.

1.55 $[H_{2}PO_{4}] + [tex][H_{2}PO_{4}]$ = 1 mM

2.55 $[H_{2}PO_{4}]$ = 1 mM

$[H_{2}PO_{4}]$ = 0.392 mM

Putting the value of $[H_{2}PO_{4}]$ in equation (1) we get the following.

0.392 mM + $[HPO_{4}]$ = 1 mM

$[HPO_{4}]$ = (1 - 0.392) mM

$[HPO_{4}]$ = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

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