A plane has a speed of 275 km/hr. The wind is at a 70 degree angle to the direction of the plane with a speed of 75 km/hr. What
1 answer:
The combined speed of the plane and the wind is 249.35 km/h.
<h3>Relative speed</h3>
The relative speed of the plane due to speed of the wind is calculated as follows;
Let the direction of the plane be horizontal direction.
<h3>Speed of the wind</h3>The speed of the wind is calculated as follows;
The combined speed of the plane and the wind is calculated as follows;
V = 275 km/h - 25.65 km/h
V = 249.35 km/h
Thus, the combined speed of the plane and the wind is 249.35 km/h.
Learn more about relative speed here: brainly.com/question/17228388
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The answer would be:
<span>It's rate of gaining speed decreases.
The rate at which speed changes is called acceleration,
You can think of this problem as an inclined plane. But the angle of an inclined plane is constantly decreasing.
We know that on a frictionless inclined plane acceleration of an object is:
</span>
<span>Where g is the gravitational acceleration of the Earth and
is the angle of an inclined plane.
Using our analogy, the ball would start on an inclined plane with a 90-degree angle and that angle would continue to decrease to zero.
The sine function is 1 at 90 degrees and is equal to zero at 0 degrees. Since our acceleration is proportional to the sine, and sine function is decreasing with the angle, our acceleration is also decreasing.
</span>
<span>It's rate of gaining speed decreases.
The rate at which speed changes is called acceleration,
You can think of this problem as an inclined plane. But the angle of an inclined plane is constantly decreasing.
We know that on a frictionless inclined plane acceleration of an object is:
</span>
<span>Where g is the gravitational acceleration of the Earth and
Using our analogy, the ball would start on an inclined plane with a 90-degree angle and that angle would continue to decrease to zero.
The sine function is 1 at 90 degrees and is equal to zero at 0 degrees. Since our acceleration is proportional to the sine, and sine function is decreasing with the angle, our acceleration is also decreasing.
</span>
Answer:
a) = 928 J
, b)U = -62.7 J
, c) K = 0
, d) Y = 11.0367 m, e) v = 15.23 m / s
Explanation:
To solve this exercise we will use the concepts of mechanical energy.
a) The elastic potential energy is
= ½ k x²
= ½ 2900 0.80²
= 928 J
b) place the origin at the point of the uncompressed spring, the spider's potential energy
U = m h and
U = 8 9.8 (-0.80)
U = -62.7 J
c) Before releasing the spring the spider is still, so its true speed and therefore the kinetic energy also
K = ½ m v²
K = 0
d) write the energy at two points, maximum compression and maximum height
Em₀ = ke = ½ m x²
= mg y
Emo =
½ k x² = m g y
y = ½ k x² / m g
y = ½ 2900 0.8² / (8 9.8)
y = 11.8367 m
As zero was placed for the spring without stretching the height from that reference is
Y = y- 0.80
Y = 11.8367 -0.80
Y = 11.0367 m
Bonus
Energy for maximum compression and uncompressed spring
Emo = ½ k x² = 928 J
= ½ m v²
Emo =
Emo = ½ m v²
v =√ 2Emo / m
v = √ (2 928/8)
v = 15.23 m / s