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kvasek [131]
2 years ago
9

A plane has a speed of 275 km/hr. The wind is at a 70 degree angle to the direction of the plane with a speed of 75 km/hr. What

is the combined speed?
Physics
1 answer:
8090 [49]2 years ago
6 0

The combined speed of the plane and the wind is 249.35 km/h.

<h3>Relative speed</h3>

The relative speed of the plane due to speed of the wind is calculated as follows;

Let the direction of the plane be horizontal direction.

<h3>Speed of the wind</h3>

The speed of the wind is calculated as follows;

V_b = V \times cos\theta\\\\V_b = 75 \times cos(70)\\\\V_b = 25.65 \ km/hr

<h3>Combined speed</h3>

The combined speed of the plane and the wind is calculated as follows;

V = 275 km/h - 25.65 km/h

V = 249.35 km/h

Thus, the combined speed of the plane and the wind is 249.35 km/h.

Learn more about relative speed here: brainly.com/question/17228388

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a tennis ball is thrown straight up with an initial velocity of 22.5 m/s how much total time is the ball in the air
lutik1710 [3]

Answer:

4.6s

Explanation:

v=u+at

0=22.5+(-9.8)t

-22.5=-9.8t

t=-22.5/-9.8

t=2.295 s

The total time will double

2.295×2=4.59s

=4.6s

6 0
3 years ago
How many stars are in the universe (approximately)? O 40 sixtillion 0 365 billion O 86.4 million O one​
Annette [7]

Answer:

a i belive

Explanation:

the univerce is VERY large so a, if im wrong i apologise :(

6 0
3 years ago
Consider a ball rolling down the decreasing slope inside a semicircular bowl (the slope is steep at the top rim, gets less steep
satela [25.4K]
The answer would be:
<span>It's rate of gaining speed decreases.
The rate at which speed changes is called acceleration, 
You can think of this problem as an inclined plane. But the angle of an inclined plane is constantly decreasing.
We know that on a frictionless inclined plane acceleration of an object is:
</span>a=gsin(\theta)
<span>Where g is the gravitational acceleration of the Earth and \theta is the angle of an inclined plane. 
Using our analogy, the ball would start on an inclined plane with a 90-degree angle and that angle would continue to decrease to zero. 
The sine function is 1 at 90 degrees and is equal to zero at 0 degrees. Since our acceleration is proportional to the sine, and sine function is decreasing with the angle, our acceleration is also decreasing.

</span>
8 0
3 years ago
“I know what the atomic number of this atom is, but I don’t know what the number of electrons is,” a friend says. How would you
liq [111]

Once the atomic number of an atom is known, the number of electrons can be deduced depending on if the atom is an ion or a neutral one.

<h3>Atomic number</h3>

The atomic number of an atom is the number of protons in the nucleus of the atom.

For atoms that are neutral, that is, no net charges, the number of protons is always equal to the number of electrons. In other words, the positive charges always balance the negative charges in neutral atoms.

Thus, if the atomic number of a neutral atom is 6, for example, the proton number will also be 6. Since the proton must balance the electron, the number of electrons will also be 6.

More on atomic numbers can be found here; brainly.com/question/17274608

8 0
2 years ago
A vertical spring has a spring constant of 2900 N/m. The spring is compressed 80 cm and a 8 kg spider is placed on the spring. T
Serga [27]

Answer:

a)  k_{e} = 928 J , b)U = -62.7 J , c) K = 0 , d) Y = 11.0367 m,  e)  v = 15.23 m / s  

Explanation:

To solve this exercise we will use the concepts of mechanical energy.

a) The elastic potential energy is

      k_{e} = ½ k x²

      k_{e} = ½ 2900 0.80²

      k_{e} = 928 J

b) place the origin at the point of the uncompressed spring, the spider's potential energy

     U = m h and

     U = 8 9.8 (-0.80)

     U = -62.7 J

c) Before releasing the spring the spider is still, so its true speed and therefore the kinetic energy also

      K = ½ m v²

      K = 0

d) write the energy at two points, maximum compression and maximum height

     Em₀ = ke = ½ m x²

     E_{mf} = mg y

     Emo = E_{mf}

     ½ k x² = m g y

     y = ½ k x² / m g

     y = ½ 2900 0.8² / (8 9.8)

     y = 11.8367 m

As zero was placed for the spring without stretching the height from that reference is

     Y = y- 0.80

     Y = 11.8367 -0.80

     Y = 11.0367 m

Bonus

Energy for maximum compression and uncompressed spring

     Emo = ½ k x² = 928 J

     E_{mf}= ½ m v²

     Emo = E_{mf}

     Emo = ½ m v²

      v =√ 2Emo / m

     v = √ (2 928/8)

     v = 15.23 m / s

8 0
4 years ago
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