An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m

Physics

1 answer:

ryzh [129]2 years ago

6 0

The work done by the applied force on the object is (2ab²i + 3b²j) J.

<h3>Magnitude of the force on the object</h3>

The magnitude of the force on the object is calculated as follows;

f = (2xyi + 3yj)

when;

x = a, and y = b

f = (2abi + 3bj)

<h3>Work done by the force</h3>

The work done the applied force is the product of force and displacement of the object.

W = fΔs

where;

Δs is displacement of the object

Δx = a - a = 0

Δy = 0 - b = -b

Δs = √(Δx² + Δy²)

Δs = √(-b)²

Δs = b

W = (2abi + 3bj) x b

W = (2ab²i + 3b²j) J

Thus, the work done by the applied force on the object is (2ab²i + 3b²j) J.

The complete question is below;

An object moving in the xy-plane is subjected to the force f = (2xyi + 3yj), where x and y are in m. The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis. How much work does the force do?

Learn more about work done here: brainly.com/question/8119756

You might be interested in

A surfer is moving at a constant velocity of 5.2 m/s north relative to a wave which is pushing him west at a constant velocity o

Vika [28.1K]

The speed and distances are directly proportional. Use ratios to solve for vertical y-distance. The ratio of x-distance west to y-distance north equals the x-velocity to y-velocity.

x/y = vx/vy
41/y = 8.6/5.2
41/y = 1.65
41/1.65 = y
24.8 m = y

5 0

3 years ago

A toy car pushed across the floor is observed to slow down and stop based on Newton’s first law of motion what is the best concl

Maksim231197 [3]

An object in motion eventually stops because of friction.

<h3>What is Newton’s first law of motion?</h3>

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or continue its moving in a straight line at constant speed unless force is applied on it.

So we can conclude that An object in motion eventually stops is the correct answer.

Learn more about law here: brainly.com/question/820417

3 0

2 years ago

All of the following are factors affecting flow rate except what?

faust18 [17]

Answer:

c. Vessel side holes

Explanation:

The "Poiseuille formula" which is given by $\\\begin{aligned} \small Q& = \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned}$ describes the volumetric flow rate ( $\small Q$ ) through tubular sections.
Here, $\Delta P,\,\, \Delta L,\,\, r,\,\, \eta$ represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.