From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

$\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)$

Solving N from (2) and replacing in (1):

$N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c$

The centripetal acceleration is given by:

$a_c=\frac{v^2}{r}$

Replacing and solving for v:

$gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}$

4 0

3 years ago

A ________ is a device that converts digital signals from a computer into analog signals so that telephone lines may be used as

kipiarov [429]

Answer:

analog-to-digital

Explanation:

An analog-to-digital converter, or ADC as it is more commonly called, is a device that converts analog signals into digital signals.

6 0

3 years ago

A woman lifts her 100-newton child up one meter and carries her for a distance of 50 meters to the 3.2

lianna [129]

(100 N) x (1 m) =<span>= 100 J

hope that helps</span>

4 0

4 years ago

a kid is flying a kite 58 meters above the level ground. a small lead sphere is dropped from the kite. calculate the amount of t

Fynjy0 [20]

This is the formula you need to memorize:

D = 1/2 · a · T²

Distance = (1/2) · (acceleration) · (Time²)

This formula tells the distance an object falls in any amount of time.

This question tells you the distance (58m), and you know the acceleration (gravity, 9.8 m/s²), so you can use this formula to find the time.

Distance = (1/2) · (acceleration) · (Time²)

58m = (1/2) · (9.8 m/s²) · (Time²)

Divide each side by (4.9 m/s²) : Time² = (58/4.9) seconds²

Take the square root of each side: <em>Time = 3.44 seconds </em>

6 0

3 years ago