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Leya [2.2K]
2 years ago
5

Xander reached a final velocity of 4.5 m/s for 3.5 seconds. Finley reached a final velocity of 3.6 m/s for 4.2 seconds. Max reac

hed a final velocity of 7.3 m/s for 1.2 seconds. They all started at the same location from rest. Which lists them from least to most acceleration? Max Finley Xander Max Xander Finley Xander Finley Max Finley Xander Max
Physics
2 answers:
ANEK [815]2 years ago
6 0

Answer:

Finley, Xander and Max

Explanation:

v = Final velocity

t = Time

u = Initial velocity = 0

a = Acceleration

From kinematic equations we get

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}=\dfrac{v-0}{t}\\\Rightarrow a=\dfrac{v}{t}

Xander

v = 4.5 m/s, t = 3.5 s

a=\dfrac{4.5}{3.5}\\\Rightarrow a=1.29\ \text{m/s}^2

Finley

v = 3.6 m/s, t = 4.2 s

a=\dfrac{3.6}{4.2}\\\Rightarrow a=0.86\ \text{m/s}^2

Max

v = 7.3 m/s, t = 1.2 s

a=\dfrac{7.3}{1.2}\\\Rightarrow a=6.083\ \text{m/s}^2

The required list is Finley, Xander and Max.

pshichka [43]2 years ago
5 0

Answer:

Finley, Xander and Max

Explanation:

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A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?
OlgaM077 [116]

Answer:

a = 2.72 [m/s2]

Explanation:

To solve this problem we must use the following kinematics equation:

v_{f} =v_{o} + a*t

where:

Vf = final velocity = 1200 [km/h]

Vo = initial velocity = 25 [km/h]

t = time = 2 [min] = 2/60 = 0.0333 [h]

1200 = 25 + (a*0.0333)

a = 35250.35 [km/h2]

if we convert these units to units of meters per second squared

35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]

3 0
3 years ago
Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is
Ivahew [28]

Answer:

4 capacitors

Explanation:

Given

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Required

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This is calculated as:

c = n - 1

So, we have:

c = 5 - 1

c = 4

8 0
2 years ago
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Tomtit [17]

Answer:

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3 years ago
A small object with a 5.0-mC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electr
kolbaska11 [484]

Answer:

0.002 N/C

Explanation:

Parameters given:

Charge of object, q = 5 mC = 5 * 10^{-3} C

Acceleration of object, a = 0.005 m/s^2

Mass of object, m = 2.0 g

The Electric field exerts a particular force on the object, causing it to accelerate (Electrostatic force).

We know that Electrostatic force, F, is given in terms of Electric field, E, as:

F = qE

This means that the object exerts a force of -qE on the Electric force (Action with equal and opposite reaction).

The object also has a force, F, due to its acceleration a. This force is the product of its mass and acceleration. Mathematically:

F = ma

Equating the two forces of the object, we get:

-qE = ma

=> E = \frac{-ma}{q}

Solving for E, we have:

E = \frac{-2 * 10^{-3} * 0.005}{5 * 10^{-3}} \\\\\\E = -0.002 N/C

The magnitude will be:

|E| = |-0.002| N/C = 0.002 N/C

The electric field has a magnitude of 0.002 N/C.

4 0
3 years ago
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Alenkasestr [34]

Answer:

True.

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A nanometer is a unit of mass, whereas a nanosecond is a unit of time. To convert 1.3 hours to minute, you would multiply by 1 h / 60 min. Kilometer is a unit of length, whereas kilogram is a unit of mass. True.

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