Answer:
1) 1/√K
2) 1/K
3) √K
Explanation:
As general rules of operation of equilibrium constants:
For the reaction:
A + B ⇄ C + D; Equilibrium constant = K
C + D ⇄ A + B; K' = 1/K
2A + 2B ⇄ 2C + 2D; K'' = K²
Thus, as equilibrium constant of:
2CO2 + 4H2O ⇄ 2CH3OH + 3O2
Is K:
1) CH3OH + 3/2 O2 ⇄ CO2 + 2H2O
K' = 1 / K^(1/2) = 1/√K
2) 2CH3OH + 3O2 ⇄ 2CO2 + 4H2O
K' = 1/K
3) CO2 + 2H2O ⇄ CH3OH + 3/2 O2
K' = K^(1/2) = √K
The atoms of hydrogen that are present in 7.63 g of ammonia(NH3)
find the moles of NH3 =mass/molar mass
7.63 g/ 17 g/mol = 0.449 moles
since there is 3 atoms of H in NH3 the moles of H = 0.449 x 3 = 1.347 moles
by use of 1 mole = 6.02 x10^23 atoms
what about 1.347 moles
= 1.347 moles/1 moles x 6.02 x10^23 atoms = 8.11 x10^23 atoms of Hydrogen
Answer:
Chemists make observations on the macroscopic a scale that lead to conclusions about microscopic features
Explanation:
Many important chemical observations are made on the macroscopic scale. This is because, many of the scientific equipments available are not presently able to provide direct evidence about microscopic processes. Evidences obtained from macroscopic observations could serve as important insights into the nature of certain microscopic processes.
This is evident in the study of the structure of the atom. Most of the evidences that led to the deduction of the atomic structure were obtained from macroscopic evidence but ultimately provided important information about the microscopic structure of the atom.
Answer:
concentration = mol/volume = 4/2 = 2M