Number of charge = 5018 C
<h3>Further explanation</h3>
Given
1000 C of charge for x grams of copper
Required
Number of charge
Solution
Faraday's Law :

For 1000 C, W = x grams

For 5x grams :

Answer:
100 j
Explanation:
bascially u j subtract 50 from 150 because the system lost 50 j but theres 150 in its surroundings
A. PV=constant
752 torr = 0.989 atm
(0.989 atm)(4.38 L) = (1.88 atm)V
V = 2.30 L
B. T/V = constant
(294 K)/(4.38 L) = (448 K)/V
V = 6.67 L
Hoped this helped ( I believe it's right, sorry if it's not )
% error = | accepted value - experimental value | / accepted value × 100
Step one- | 4.15mL - 4.26mL | = 0.11
Step two- 0.11 / 4.15 = 0.027
Step three- -0.027 × 100 = 2.7%