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Vikentia [17]
3 years ago
15

HELP ME with THIS I am time i have a little bit of time and still have more questions !!! CHEMISTRY!!

Chemistry
1 answer:
rosijanka [135]3 years ago
3 0

Answer:

1. is B 2. is C or B

Explanation:

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State Hund's rule.
loris [4]

Answer:

C. The lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, all of which have the same spin, in degenerate orbitals.

Explanation:

The Hund's rule is used to place the electrons in the orbitals is it states that:

1. Every orbital in a sublevel is singly occupied before any orbital is doubly occupied;

2. All of the electrons in singly occupied orbitals have the same spin.

So, the electrons first seek to fill the orbitals with the same energy (degenerate orbitals) before paring with electrons in a half-filled orbital. Orbitals doubly occupied have greater energy, so the lowest-energy electron configuration of an atom has the maximum number of unpaired electrons, and for the second statement, they have the same spin.

The other alternatives are correct, but they're not observed by the Hund's rule.

6 0
3 years ago
Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e
igor_vitrenko [27]

Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em>  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

Explanation:

1) Moles of NaCl ,n_1=1 mol

Mass of water = m= 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute(NaCl)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p=17.19 Torr

The vapor pressure for the NaCl solution at 17.19 Torr.

2) Moles of sucrose ,n_1=1mol

Mass of water = m  = 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p'

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute ( glucose)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p'=17.19 Torr

The vapor pressure for the glucose solution at 17.19 Torr.

p = p' = 17.19 Torr

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

3 0
3 years ago
I need help with this ASAP.
adelina 88 [10]

Answer:

bob

Explanation:

owa owa owa

3 0
3 years ago
The isomerization of cyclopropane to propylene is a first-order process with a half-life of 19 min at 500°c. the time it takes f
amid [387]
<span>As mentioned, the isomerization of cyclopropane to propylene is a first-order process with a half-life of 19 min at 500°c. A first-order reaction kinetic rates means that the rate is constant throughout the reaction.

Thus, the time it takes for the partial pressure of cyclopropane to decrease from 1 atm to 0.125 atm at 500°c is </span><span>57 minutes.</span>
3 0
3 years ago
What are the substances making up a mixture called
dimulka [17.4K]

  • The substance that made up of a particular mixture can be regarded as Solute and solvent

  • A  mixture can be regarded as material which is made up of  more than one  different Chemical substance or substances , whereby they  are not chemically combined.

  • Substance could be any matter such as <em>salt, rice, and or compounds</em>

  • A mixture can be regarded as physical combination involving two or more substances whereby each entities identities are retained, then mixed in the form such as ;
  1. <em>solutions</em>
  2. <em> suspensions </em>
  3. <em> colloids</em>.

  • A mixture could be  in this form <em>(Solute + solvent = solution)</em>

Therefore, the substance that made up of a particular mixture can be regarded as <em>Solute and solvent</em>

Learn more at: brainly.com/question/18569341

7 0
3 years ago
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