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3 years ago

When electric current is passed through acidulated water.

Chemistry

2 answers:

kirill [66]3 years ago

7 0

Answer:

Water decomposes into hydrogen and oxygen on passing electric current through acidulated water. Therefore, it is a decomposition reaction.

Explanation:

When an electric current is passed through acidulated water, it will produce a reaction called electrolysis. If an electric current is passed through acidified water, then bubbles of oxygen gas(O2) and hydrogen(H2) gas are produced at the two electrodes immersed in it.

nordsb [41]3 years ago

5 0

$\bold{\boxed{\huge{\blue{\underline{Answer }}}}}$

When electric current is passed through acidulated water , then it split into hydrogen and oxygen molecule that is H2 and O2 

Chemical equation for above reaction :-

2H20 on electrolysis given 2H2 + O2

This spilliting of water due to electricity is called electrolysis .

In electrolysis, H2 moves towards cathode as it forms positive ions whereas O2 moves towards anode as it forms negative ions .

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3 years ago

2. The Density of Water is 1.0000g/cm3. Based on this property of water,

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Answer:

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Explanation:

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3 years ago

How does bohrs model agree with Thomson model

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3 years ago

Read 2 more answers

A balloon of hydrogen is subjected to vacuum. The initial pressure and volume of hydrogen is 0.95 atm and 0.55 L. Calculate the

Scilla [17]

Answer:

0.43 atm

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 0.95 atm

Initial volume (V₁) = 0.55 L

Final volume (V₂) = 1.22 L

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as follow:

P₁V₁ = P₂V₂

0.95 × 0.55 = P₂ × 1.22

0.5225 = P₂ × 1.22

Divide both side by 1.22

P₂ = 0.5225 / 1.22

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Therefore, the final pressure of the gas is 0.43 atm

7 0

3 years ago

consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

MakcuM [25]

Answer:

CaO is the limiting reagent

Theoritical yield = 25.71 g

% Yield = 75.44%

Explanation:

1 mole = Molar mass of the substance

Molar Mass of CaO = 56 g/mol

Molar Mass of CaCO3 = 100 g/mol

Molar mass of CO2 = 44 g/mol

The balanced Equation is :

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO reacts with = 1 mole of CO2

56 g of CaO reacts with = 44 g of CO2

1 g of CaO reacts with =

$\frac{44}{56}$

= 0.785 g of CO2

So,

14.4 g of CaO must react with = (14.4 x 0.785) g of CO2

= 11.31 g of CO2

Needed = 11.31 g

Available CO2 = 13.8 g (given)

So CO2 is in excess , hence CaO is the limiting reagent and product will produce from 14.4 g of CaO

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO will produce 1 mole pf CaCO3

56 g of CaO produce = 100 g of CaCO3

1 g of CaO produce =

$\frac{100}{56}$

= 1.785 g of CaCO3

14.4 g of CaO will produce = (1.785 x 14.4) g of CaCO3

= 25.71 g of CaCO3

Theoritical Yield of CaCO3 = 25.71 g

Actual yield = 19.4 g

Percent Yield =

$\frac{Actual\ yield}{Theoritical\ yield}\times 100$

$\frac{19.4}{25.71}\times 100$

= 75.44 %

6 0

3 years ago

When electric current is passed through acidulated water.​

When electric current is passed through acidulated water.