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Delicious77 [7]
3 years ago
6

A ball rolls down a hill, starting from rest. How long is it rolling if it accelerates at 3m/s2 and ends with a velocity of 35m/

s?
Physics
1 answer:
Kryger [21]3 years ago
6 0
<h2>Answer</h2>

The answer to this question is 11.67 s

<h2>Explanation</h2>

As we know that accelartion is the rate of change of velocity. So, it can be write as

a = (V_f -V_i) /t

where

V_f is the final velocity

V_i is the initial velocity

t is the time

a is the accelartion

as we konw

a = 3 ms^{-2}

t = ?

From rest So,

V_i = 0

V_f = 35 ms^{-1}

Putting values

3 = (35 - 0)/t

3 = 35/t

t = 35/3

t = 11.67 s

So, the right answe is 11.67 s

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<u>(a)</u>

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