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Delicious77 [7]
3 years ago
6

A ball rolls down a hill, starting from rest. How long is it rolling if it accelerates at 3m/s2 and ends with a velocity of 35m/

s?
Physics
1 answer:
Kryger [21]3 years ago
6 0
<h2>Answer</h2>

The answer to this question is 11.67 s

<h2>Explanation</h2>

As we know that accelartion is the rate of change of velocity. So, it can be write as

a = (V_f -V_i) /t

where

V_f is the final velocity

V_i is the initial velocity

t is the time

a is the accelartion

as we konw

a = 3 ms^{-2}

t = ?

From rest So,

V_i = 0

V_f = 35 ms^{-1}

Putting values

3 = (35 - 0)/t

3 = 35/t

t = 35/3

t = 11.67 s

So, the right answe is 11.67 s

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Answer:

The answer is 45 degree angle

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3 years ago
A heater is being designed that uses a coil of 14-gauge nichrome wire to generate 300 W using a voltage of V = 110 V . How long
Mazyrski [523]

Answer:

The length of the wire is 83.2 m.

Explanation:

Given that,

Power of heater, P = 300 W

Voltage, V = 110 V

The resistivity of nichrome wire is, \rho=100\times 10^{-8}\ \Omega-m

The electric power of a wire is given by :

P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{300}\\\\R=40.34\ \Omega

Area of cross section of the wire is :

A=\pi r^2\\\\A=\pi (0.000815)^2\\\\A=2.08\times 10^{-6}\ m^2

Resistance of a material is given by :

R=\rho \dfrac{L}{A}\\\\L=\dfrac{RA}{\rho}\\\\L=\dfrac{40\times 2.08\times 10^{-6}}{10^{-6}}\\\\L=83.2\ m

So, the length of the wire is 83.2 m. Hence, this is the required solution.

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3 years ago
What is it called when objects become positively charged when they lose electrons and negatively charged when they gain electron
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4 0
3 years ago
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An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad / s). if a particular disk is spun at 79
NeX [460]
(i) |α| = 235.6rad.s / 0.502s = 469 rad/s²
(ii) tang a = α*r = 469rad/s² * 0.12m / 2*11 = 2.56 m/s²
4 0
3 years ago
Hey stob it.<br> Please help me.<br> Cmon help me.<br> Plz.
Anna [14]

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

6 0
2 years ago
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