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Delicious77 [7]

3 years ago

6

A ball rolls down a hill, starting from rest. How long is it rolling if it accelerates at 3m/s2 and ends with a velocity of 35m/

s?

1 answer:

Kryger [21]3 years ago

6 0

<h2>Answer</h2>

The answer to this question is $11.67 s$

<h2>Explanation</h2>

As we know that accelartion is the rate of change of velocity. So, it can be write as

$a = (V_f -V_i) /t$

where

$V_f$ is the final velocity

$V_i$ is the initial velocity

t is the time

a is the accelartion

as we konw

$a = 3 ms^{-2}$

t = ?

From rest So,

$V_i$ = 0

$V_f = 35 ms^{-1}$

Putting values

$3 = (35 - 0)/t$

$3 = 35/t$

$t = 35/3$

$t = 11.67 s$

So, the right answe is $11.67 s$

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2 years ago

Which ball has the greater average speed during the 1-s interval after release (assuming neither hits the ground during that tim

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Answer:

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