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nirvana33 [79]
3 years ago
15

Porque a las vacunas los cientificos las llaman reactivos.​

Chemistry
1 answer:
yan [13]3 years ago
5 0

Answer:

Because scientists call vaccines reagents.

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hydrogen combines with sulfur much like hydrogen combines with oxygen draw an electron dot diagram showing hydrogen combined wit
sertanlavr [38]

hydrogen combines with sulfur is H2S

<span> hydrogen combines with oxygen H2O</span> <span>Hydrogen sulfide<span> <span>is the </span></span>chemical compound<span> <span>with the </span></span>formula <span>H<span>
2S</span></span>. It is a colorless gas<span> <span>with the characteristic foul odor of rotten </span></span>eggs<span>; it is heavier than air, very poisonous, corrosive, flammable, and explosive; properties shared with the denser </span>hydrogen chalcogenides</span>

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6 0
3 years ago
Perform the following operation
lukranit [14]

Answer:

(5.4 x 10³) x (1.2 x 10⁷) = 6.48 x 10¹⁰

With correct significant figures, the answer would be 6.5 x 10¹⁰.

4 0
2 years ago
I need some chem help :(
alexandr402 [8]
Hi, can you post what you need help with??
7 0
3 years ago
Which of the following correctly describes the difference (on average) between an electron in a 2s orbital and an electron in a
bulgar [2K]

Answer:

C: electrons is the 3s orbital are higher than those in the 2s orbital

Explanation:

Looking at the options, the correct one is that the electrons in the 3s orbital will possess more energy than those in the 2s orbital. This is because the the 2s orbitals will be filled with electrons first before the 3s orbital.

Also from basics we know that the energy of an orbital increases as the quantum number increases.

4 0
3 years ago
The wavelength propagates to 15 m with a frequency of 0.3 HZ<br><br> What is the speed of this wave?
ololo11 [35]

Answer:

c=50\frac{m}{s}

Explanation:

Hello!

In this case, given the relationship between velocity, wavelength and frequency:

c=\lambda *f

By plugging in the given wavelength and frequency, we obtain the following speed:

c=15m*0.3\frac{1}{s}\\\\c=50\frac{m}{s}

Best regards!

8 0
3 years ago
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