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klasskru [66]
2 years ago
5

Find the temperature

Physics
1 answer:
NNADVOKAT [17]2 years ago
8 0

Answer:

-------1

Explanation:

beacuse that is what i know

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basic component of matter, it is composed of a nucleus which is the central part, the protons and electorns
Troyanec [42]
Atoms are the basic components of matter
5 0
3 years ago
A weightlifter uses a force of 356 N to lift a set of weights 2.2 m off the ground. How much work did the weightlifter do? Answe
Valentin [98]

Answer:

783.2 N.m or Joules

Explanation:

W=F*d*cos(Ф)

Work done when a force F is applied to move an object by a displacement d meters

where cos(Ф) is the angle between applied force F and displacement d

Since the weightlifter is applying the force upward and the set of weight also move upward therefore, both are in same direction hence angle will be zero.

Now lets substitute the given values into the work equation:

W=356*2.2*cos(0)

since cos(0)=1

W=356*2.2*1

W=783.2 N.m

or

W=783.2 Joules

Since the unit of Force is Newton (N) and the unit of displacement is meters (m) therefore, unit of work done will be N.m

Note: 1 N.m is equivalent to 1 joule

7 0
3 years ago
Two children sit on different sides of a seesaw. The first child of mass 27 kg sits 1.5 m from the center. How far must the seco
erma4kov [3.2K]

Answer:

dhdhhdshdhdhsjsnsjdnnsjsjshsjsndnsnsnsnzsnsnsnsjzjsjsjsjj

Explanation:

jsjszhxhbssbzbbzbdfnndsndnndndnsndnfndndnsmsnsxnbdbsndndndnxbcbwnnbfndbdxbbdbvh go do some gehehhsdhehndnsbxhdbdj

5 0
4 years ago
1. A step-up transformer increases 15.7V to 110V. What is the current in the secondary as compared to the primary? Assume 100 pe
Serjik [45]

1. I_2 = 0.14 I_1

Explanation:

We have:

V_1 = 15.7 V voltage in the primary coil

V_2 = 110 V voltage in the secondary coil

The efficiency of the transformer is 100%: this means that the power in the primary coil and in the secondary coil are equal

P_1 = P_2\\V_1 I_1 = V_2 I_2

where I1 and I2 are the currents in the two coils. Re-arranging the equation, we find

\frac{I_2}{I_1}=\frac{V_1}{V_2}=\frac{15.7 V}{110 V}=0.14

which means that the current in the secondary coil is 14% of the value of the current in the primary coil.

2. 5.7 V

We can solve the problem by using the transformer equation:

\frac{N_p}{N_s}=\frac{V_p}{V_s}

where:

Np = 400 is the number of turns in the primary coil

Ns = 19 is the number of turns in the secondary coil

Vp = 120 V is the voltage in the primary coil

Vs = ? is the voltage in the secondary coil

Re-arranging the formula and substituting the numbers, we find:

V_s = V_p \frac{N_s}{N_p}=(120 V)\frac{19}{400}=5.7 V

5 0
3 years ago
A total of 875 J of work was done when a force of 175 N was exerted on a box to move it. How far was the box moved
Vladimir [108]
Work = Force times Distance
W = Fd

Given W = 750J, F = 125N;

750 = 125d

Solving for d:
d = 750/125
d = 6

The box moved a distance of 6 meters.
3 0
2 years ago
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