Answer:
0.535 g
Explanation:
The reaction that takes place is:
- NaCl + AgNO₃ → AgCl + NaNO₃
First we <u>calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- moles = Molarity * liters
<em>Converting 25.0 mL to L </em>⇒ 25.0 / 1000 = 0.025 L
- moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃
Then we <u>convert AgNO₃ moles into NaCl moles</u>:
- 0.00915 mol AgNO₃ *
= 0.00915 mol NaCl
Finally we<u> convert NaCl moles into grams</u>, using its <em>molar mass</em>:
- 0.00915 mol NaCl * 58.44 g/mol = 0.535 g
First, to convert from C to K, add (C+273)=k
So -25+273=248
<span>C. More than two electrons can be transferred in ionic bonds or shared in covalent bonds.</span>
1 mole of propane = 6.02*10^23 propane molecules
<span>2.12 moles of propane = 1.27624*10^24 propane molecules </span>
Answer:
The answer is "
"
Explanation:
Please find the complete question in the attached file.
Formula:

