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Digiron [165]
2 years ago
6

N/ student/teerdządg

Chemistry
1 answer:
Harlamova29_29 [7]2 years ago
3 0

Answer:

B

Explanation:

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Please help with Chem I DON'T HAVE ENOUGH TIME!
Kamila [148]

<u>We are given:</u>

Mass of water: 119 grams

We know that one mole of a gas occupies 22.4L of volume

<u>Number of moles of water:</u>

Number of moles = given mass / Molar mass

Number of moles = 119 / 18             [molar mass of water = 18 grams/mol]

Number of moles = 6.61 moles

<u>Volume occupied:</u>

Volume = number of moles * 22.4 L

Volume = 6.61 * 22.4

Volume = 148L

Volume (in mL) = 1.48 * 10⁻¹ mL

7 0
3 years ago
Read 2 more answers
How many grarns would 3 moles of carbon dioxide (CO2) weigh? (round to the
BigorU [14]

Mass of CO₂ = 132 g

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mole also can be formulated :

\tt n=\dfrac{mass}{MW}

moles of CO₂ = 3

mass of CO₂(MW=44.01 g/mol) :

\tt mass=mol\times MW\\\\mass=3\times 44.01\\\\mass=132.03~g\approx 132~g

6 0
3 years ago
If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
Evgesh-ka [11]

Answer:

E. None of these

Explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

\frac{P1V1}{RT1} = \frac{P2V2}{RT2}

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

\frac{1*20}{R*10} = \frac{10*V2}{R*100}

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

\frac{1*20*100}{10*10} = V2

∴ V2 = \frac{2000}{100}

∴ V2 = 20mL

3 0
2 years ago
Sodium-potassium pumps are examples of what type of cellular transport?
Dmitrij [34]

Answer:

Active transport

Explanation:

Sodium-potassium pumps are examples of Active type of cellular transport. Sodium potassium pump exchanges sodium ions from potassium ions through the plasma membrane of animal cells.

Whereas Active transport can be defined as movement of ions and molecules across a cell membrane to the region  of higher concentration with the help of enzymes and energy.

5 0
4 years ago
In a solution the solute is the substance present in the greatest amount true or false
kati45 [8]
Solute is something that is being dissolved { ex : sugar , salt} 

Solvent is something that has ability to dissolve things { ex : water}

False because the solvent is present in larger amounts...
3 0
4 years ago
Read 2 more answers
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