Answer:
Police officer
Explanation:
Because police officers wants to gather information on what happens and question people to know everything. That is what Derick is doing
Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density
<h3>What is anomalous expansion of water?</h3>
Anomalous expansion of water is a property of water in which water expands instead of contracting.
- Anomalous expansion of water makes water less dense.
- The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
- Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.
Learn more about properties of water:
brainly.com/question/18681949
Answer:
it is 3
Explanation:
because the crack will be open for the magma to come out
Answer:
Resistance = 252.53 Ohms
Explanation:
Given the following data;
Charge = 0.125 C
Voltage = 5 V
Time = 6.3 seconds
To find the resistance;
First of all, we would determine the current flowing through the battery;
Quantity of charge, Q = current * time
0.125 = current * 6.3
Current = 0.125/6.3
Current = 0.0198 A
Next, we find the resistance;
Resistance = voltage/current
Resistance = 5/0.0198
Resistance = 252.53 Ohms
Answer:
The puck moves a vertical height of 2.6 cm before stopping
Explanation:
As the puck is accelerated by the spring, the kinetic energy of the puck equals the elastic potential energy of the spring.
So, 1/2mv² = 1/2kx² where m = mass of puck = 39.2 g = 0.0392 g, v = velocity of puck, k = spring constant = 59 N/m and x = compression of spring = 1.3 cm = 0.013 cm.
Now, since the puck has an initial velocity, v before it slides up the inclined surface, its loss in kinetic energy equals its gain in potential energy before it stops. So
1/2mv² = mgh where h = vertical height puck moves and g = acceleration due to gravity = 9.8 m/s².
Substituting the kinetic energy of the puck for the potential energy of the spring, we have
1/2kx² = mgh
h = kx²/2mg
= 59 N/m × (0.013 m)²/(0.0392 kg × 9.8 m/s²)
= 0.009971 Nm/0.38416 N
= 0.0259 m
= 2.59 cm
≅ 2.6 cm
So the puck moves a vertical height of 2.6 cm before stopping
