Answer:
Mass of KNO3 in the original mix is 146.954 g
Explanation:
mass of 
in original 254.5 mixture.
moles of 
moles of
= 0.2926 mol of BaSO4
Therefore,
0.2926 mol of BaCl2,
mass of 
= 60.92 g
the AgCl moles 
= 1.3891 mol of AgCl
note that, the Cl- derive from both, 
so
mole of Cl- f NaCl 
mol of Cl-
mol of NaCl = 0.8039 moles
then
KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3
Mass of KNO3 in the original mix is 146.954 g
Answer: The result section of the project contains your findings while carrying out your research or study.
Explanation:
The Results section of a research or study usually contains only the findings of your study or research.The findings which usually include
1. Data presented in tables, charts, graphs, and other figures.
2. A contextual analysis of this data explaining its meanings. Usually in sentences.
Our result gotten is not discussed in result section because every project or research work has a discussion page where every results or findings are discussed. The result section is expected to carry what you found.
Answer: B). little wind
Explanation: Deserts have few large animals, fertile soil, and little rainfall but they have lots of wind
Answer:
10 molecules of NH₃.
Explanation:
N₂ + 3H₂ --> 2NH₃
As the N₂ supply is unlimited, what we need to do to solve this problem is <u>convert molecules of H₂ into molecules of NH₃</u>. To do so we use the <em>stoichiometric coefficients</em> of the balanced reaction:
- 15 molecules H₂ *
= 10 molecules NH₃
10 NH₃ molecules could be prepared from 15 molecules of H₂ and unlimited N₂.
When an electron transit from lower level to higher level it emits energy
When an electron transit from higher level from a lower level it absorbs energy
n=3 to n=5, : absorption
n=1 to n=3, : absorption
n=3 to n=2, : emission
n=2 to n=1 : emission
the highest energy means highest wave number
wave number = Rh (1/ n1^2 - 1/n2^2)
Rh = 1.1 X 10^7 m^-1
1) n=3 to n=5
wavenumber = Rh ( 1/ 9 - 1/ 25) = 0.071 Rh
2) n=1 to n=3
wavenumber = Rh ( 1- 1/9 ) = 0.89 Rh
3) n=3 to n=2
wavenumber = Rh ( 1/4 - 1/9) = 0.139 Rh
4) n=2 to n=1
wavenumber = Rh ( 1- 1/4) = 0.75 Rh
Thus for 2) n=1 to n=3 energy will be maximum
