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larisa [96]
2 years ago
8

What is the scientific term for the curved shape that results? guatured cyclinder

Chemistry
1 answer:
AnnyKZ [126]2 years ago
4 0

Answer:

Curvature

Explanation:

In mathematics, curvature is any of several strongly related concepts in geometry. Intuitively, the curvature is the amount by which a curve deviates from being a straight line, or a surface deviates from being a plane. For curves, the canonical example is that of a circle, which has a curvature ... For being meaningful, the definition of the curvature and its different

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If 38g of sodium hydroxide reacts with 28g of carbon, how many grams of sodium carbonate are produced?
scZoUnD [109]

Answer:

Mass of sodium carbonate = 33.92 g

Explanation:

Given data:

Mass of sodium hydroxide = 38 g

Mass of carbon = 28 g

Mass of sodium carbonate produced = ?

Solution:

Chemical equation:

6NaOH + 2C → 2Na + 3H₂ + 2Na₂CO₃

Now will calculate the number of moles of reactants:

Number of moles of sodium hydroxide:

Number of moles = mass / molar mass

Number of moles = 38 g/ 40 g/mol

Number of moles = 0.95 mol

Number of moles of carbon:

Number of moles = mass / molar mass

Number of moles = 28 g/ 16 g/mol

Number of moles = 1.75 mol

Now we will compare the moles of both reactant with sodium carbonate.

                         C           :         Na₂CO₃

                         2           :           2

                       1.75         :         1.75

                  NaOH          :       Na₂CO₃      

                    6               :           2

                     0.95       :           2/6×0.95 = 0.32  

Number of moles of sodium carbonate produced by sodium hydroxide are less so it will limiting reactant.

Mass of sodium carbonate:

Mass = number of moles × molar mass

Mass = 0.32 mol × 106 g/mol

Mass = 33.92 g

5 0
2 years ago
Significant digits are the number of digits that reflect the precision of a measurement or number. true or false
Marizza181 [45]
Im pretty certain thats true.
5 0
3 years ago
) How many molecules are in 23 moles of Sodium?
densk [106]
4)<span>1.24⋅<span>1024</span></span><span> formula units

</span>1 mole Na<span> (sodium)</span>
6 0
2 years ago
Pls help!!!!
iogann1982 [59]

Answer: b

Explanation:

its b

3 0
3 years ago
A student wishes to calculate the experimental value of Ksp for AgI. S/he follows the procedure in Part 3 and finds Ecell to be
Ymorist [56]

Answer:

a)    [Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)    1.273 × 10⁻¹⁶

c)    2.629×10⁻¹⁹ M Thus; the value for  [Ag+ ]dilute will be too low

Explanation:

In an Ag | Ag+ concentration cell ,

The  anode reaction can be written as :

Ag ----> Ag+(dilute) + e-    &:

The  cathode reaction can be written as:

Ag+(concentrated) + e- ----> Ag

The  Overall Reaction : is

Ag+(concentrated) -----> Ag+(dilute)

However, the Standard Reduction potential of cell = E°cell = 0

( since both cathode and anode have same Ag+║Ag )

Also , given that the theoretical slope is - 0.0591 V

Therefore; the reduction potential of cell ; i.e

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

0.839 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 14.1963  

[Ag+]dilute = \mathbf{10^{-14.1963} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)

AgI ----> Ag + (dilute) + I⁻

So , Solubility product = Ksp = [Ag⁺]dilute × [I⁻]  

= 6.363 × 10⁻¹⁶ M × 0.20 M  

= 1.273 × 10⁻¹⁶

c) If s/he mistakenly uses 1.039 V as Ecell; then the value for [Ag+]dilute will be :

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

1.039 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 17.5804  

[Ag+]dilute = \mathbf{10^{-17.5804} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 2.629×10⁻¹⁹ M

Thus, the value for  [Ag+ ]dilute will be too low

5 0
3 years ago
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