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3 years ago

Existing rocks can become sedimentary rocks when they are subjected to which conditions?

1 answer:

4 0

The correct answer is C. Since that really was a tricky question I made sure it was correct by checking on Google. Hope I helped! - Amber

You might be interested in

Consider a heat pump that operates on the reversed Carnot cycle with R-134a as the working fluid executed under the saturation d

Schach [20]

Answer:

Work out = 28.27 kJ/kg

Explanation:

For R-134a, from the saturated tables at 800 kPa, we get

$h_{fg}$ = 171.82 kJ/kg

Therefore, at saturation pressure 140 kPa, saturation temperature is

$T_{L}$ = -18.77°C = 254.23 K

At saturation pressure 800 kPa, the saturation temperature is

$T_{H}$ = 31.31°C = 304.31 K

Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.

Thus, $q_{reject}$ = $h_{fg}$ = 171.82 kJ/kg

We know COP of heat pump

COP = $\frac{T_{H}}{T_{H}-T_{L}}$

= $\frac{304.31}{304.31-254.23}$

= 6.076

Therefore, Work out put, W = $\frac{q_{reject}}{COP}$

= 171.82 / 6.076

= 28.27 kJ/kg

8 0

3 years ago

4. With regard to the pH scale, a solution with a pH

pentagon [3]

Answer:

A. Close to 14 is considered a strong base

Explanation:

A substance with a pH close to 14 is considered a strong base

PLEASE DO MARK ME AS BRAINLIEST IF MY ANSWER IS HELPFUL ;) 

5 0

3 years ago

You want to go jogging at a nearby park. your mother says a thunderstorm is five miles away. the safest thing to do in this situ

sdas [7]

Answer:

"find an indoor place to exercise"

I think that golf courses call in the golfers if there is a lightning strike within 5 miles of the golf course sensor.

7 0

2 years ago

What is the wavelength of a sound wave with a speed of 331 m/s and a frequency of 500 Hz?

ludmilkaskok [199]

Answer:

0.777m

Explanation:

The sound wave has a wavelength of 0.773m.

Explanation:

To solve this problem we have to use the wave equation that is given below:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

λ :

λ = v f

Let's plug in our given values and see what we get!

λ = 340 m s

440 s − 1

λ = 0.773 m

Hope this helps, Mark as brainliest if u want

4 0

2 years ago

Infrared radiation has frequencies from 3.0×1011 to 3.0×1014 Hz, whereas the frequency region for microwave radiation is 3.0×108

igor_vitrenko [27]

Answer:

1. The speed of infrared radiation is the same as microwave radiation.

2. The wavelength of infrared radiation is lower than microwave radiation.

Explanation:

1. The speed of infrared radiation is the same as microwave radiation. This is because both infrared radiation and microwave radiation are electromagnetic waves and all electromagnetic waves move at the same speed, the speed of light.

2. Frequency and wavelength has an inverse relationship. This means that the higher the frequency, the lower the wavelength.

Since the frequency range of infrared waves is higher than that of microwaves, the wavelength range of infrared waves is lower than that of microwaves.

We can prove this by using the maximum frequency value of each wave to calculate their corresponding wavelengths.

Speed of light, c, is given as:

c = λf

Where λ is wavelength and f is frequency.

Wavelength is therefore:

λ = c/f

For infrared wave, the maximum frequency is 3 * 10^14 Hz, hence the corresponding wavelength is:

λ = (3 * 10^8) / (3 * 10^14)

λ = 10^(-6) m

For microwave, the maximum frequency is 3 * 10^11 Hz, hence the corresponding wavelength is:

λ = (3 * 10^8) / (3 * 10^11)

λ = 10^(-3) m

Hence, the wavelength of infrared waves is lower than the wavelength of microwaves.

8 0

3 years ago