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Vanyuwa [196]
3 years ago
5

As fuel is burned in an electrical generator, the chemical energy of the fuel is converted into thermal energy that is used to b

oil water. after the steam from the boiling water moves through the pipe, what sequence of energy transformation best describes what happens?
Answer choices:
A:mechanical ----> electrical ---> light
B: light ----> electrical----> mechanical
C: Electrical---> Mechanical----> light
D: Mechanical----> light ----> electrical ​
Physics
1 answer:
amid [387]3 years ago
3 0

Answer: A

Explanation:

You might be interested in
Hey help me and thanks in advance if you do​
blsea [12.9K]

P = W / t

2000 = 30000 / t

t = 30000/2000

t = 30/2

t = 15 seconds

3 0
3 years ago
Read 2 more answers
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
shtirl [24]

Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m

Explicación:

Dado lo siguiente:

Altura desde la cual se cae el cuerpo = 120 m

Tiempo (t) = 2.5s

A.) La velocidad que toma:

El cuerpo cayó desde una altura;

velocidad inicial (u) = 0

Para calcular v:

V = u + en

Donde a = aceleración debido a la gravedad = 9.8m / s

v = 0 + (9.8) (2.5)

v = 24.5 m / s

B) Cuánto ha disminuido.

Usando la ecuación de movimiento:

S = ut + 0.5at ^ 2

Donde S = distancia

S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)

S = 0 + 0.5 (9.8) (6.25)

S = 30.625 m

Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m

C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m

5 0
3 years ago
A CD spins at a constant angular velocity of 5.0 revolutions per second clockwise.
Lera25 [3.4K]

The true statement about the CD is:

<h3><em>b. No net torque acts on it at all.</em></h3>

\texttt{ }

<h3>Further explanation</h3>

Centripetal Acceleration can be formulated as follows:

\large {\boxed {a = \frac{ v^2 } { R } }

<em>a = Centripetal Acceleration ( m/s² )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

\texttt{ }

Centripetal Force can be formulated as follows:

\large {\boxed {F = m \frac{ v^2 } { R } }

<em>F = Centripetal Force ( m/s² )</em>

<em>m = mass of Particle ( kg )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

Let us now tackle the problem !

\texttt{ }

<em>Complete Question:</em>

<em>A CD spins at a constant angular velocity of 5.0 revolutions per second clockwise. Which of the following statements about the CD is true?</em>

<em>a. A net torque acts on it clockwise to keep it moving</em>

<em>b. No net torque acts on it at all.</em>

<em>c. A net torque acts on it counterclockwise to keep it moving</em>

<u>Given:</u>

angular velocity = ω = 5.0 revolutions per second

<u>Asked:</u>

net torque = Στ = ?

<u>Solution:</u>

Constant angular velocity → angular acceleration = α = 0 rad/s²

\Sigma \tau = I \alpha

\Sigma \tau = I (0)

\Sigma \tau = 0 \texttt{ Nm}

\texttt{ }

<h3>Conclusion:</h3>

The true statement about the CD is:

<em>b. No net torque acts on it at all.</em>

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

\texttt{ }

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

#LearnWithBrainly

8 0
3 years ago
If the ball reaches the ground in 8 seconds and the velocity of the ball before it hits the ground is 78.4. What is its accelera
Natasha2012 [34]

Answer:

9.8 m / s^2

Explanation:

Assuming free fall====> there is no initial downward/upward velocity

  Assuming metric units   78.4<u>  m/s </u>

 vf = a t

 78.4 = a (8)     shows     a = 9.8 m/s^2

6 0
2 years ago
The world energy consumption was about 6*10^22 J. How much area must a parallel plate capacitor need to store this energy Assume
Nastasia [14]

Answer:

A = 5 \times 10^{32} m^2

Explanation:

As we know that the energy stored in the capacitor is given as

Q = \frac{1}{2}CV^2

here we know that

Q = 6 \times 10^{22} J

also we know that

V = 5 Volts

now we have

6 \times 10^{22} = \frac{1}{2}C(5^2)

C = 4.8 \times 10^{21} F

now we know the formula of capacitance

C = \frac{\epsilon_0 A}{d}

4.8 \times 10^{21} = \frac{(8.85 \times 10^{-12})(A)}{1}

A = 5 \times 10^{32} m^2

3 0
3 years ago
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