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rodikova [14]
2 years ago
14

How many moles are in 63 g of NH4 (molar mass= 18g)?

Chemistry
2 answers:
sdas [7]2 years ago
4 0

To answer this question, all you to do is to divide the mass by the molar mass and that should get you your moles.

=63g\ NH_{4}\ x\ \frac{1\ mol\ NH_{4}}{18g\ NH_{4}}

<em>= 3.5 mol NH₄</em>

<em></em>

<em></em>

Natalka [10]2 years ago
3 0

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

\qquad \sf  \dashrightarrow \: 18g = 1 \: mole

\qquad \sf  \dashrightarrow \: 1g =  \dfrac{1}{18}  \: moles

\qquad \sf  \dashrightarrow \: 63g =  \dfrac{1}{18}   \times 63\: moles

\qquad \sf  \dashrightarrow \: 63g =  \dfrac{7}{2}    \: moles

\qquad \sf  \dashrightarrow \: 63g = 3.5  \: moles

Correct choice is C

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Hello.

In this case, we can understand a higher entropy when more disorder is present and a lower entropy when less disorder is present, thus:

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Best regards.

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