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rodikova [14]
2 years ago
14

How many moles are in 63 g of NH4 (molar mass= 18g)?

Chemistry
2 answers:
sdas [7]2 years ago
4 0

To answer this question, all you to do is to divide the mass by the molar mass and that should get you your moles.

=63g\ NH_{4}\ x\ \frac{1\ mol\ NH_{4}}{18g\ NH_{4}}

<em>= 3.5 mol NH₄</em>

<em></em>

<em></em>

Natalka [10]2 years ago
3 0

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

\qquad \sf  \dashrightarrow \: 18g = 1 \: mole

\qquad \sf  \dashrightarrow \: 1g =  \dfrac{1}{18}  \: moles

\qquad \sf  \dashrightarrow \: 63g =  \dfrac{1}{18}   \times 63\: moles

\qquad \sf  \dashrightarrow \: 63g =  \dfrac{7}{2}    \: moles

\qquad \sf  \dashrightarrow \: 63g = 3.5  \: moles

Correct choice is C

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3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

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In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

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