With speeds up to 90 miles per hour, what is the fastest sport on ice?.
1 answer:
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The concept to solve this problem is related to the relativistic physics for which the speed of the object in different frames of reference is related. This concept is called Velocity-addition formula
and can be written as,
Where,
u = Velocity of a body within a Lorentz Frame
v = Velocity of a second frame
u'= The transformed velocity of the body within the second frame
c = speed of light
Replacing we have to
Therefore the meteor moving with respect to the Earth to 230'700.000m/s
Answer:
rom level n = 7 to level n = 3
Explanation:
Bohr's model describes the energy levels for the hydrogen atom
En = -13.606 / n²
Where n is an integer with values of 1, 2, 3
An electronic transition occurs between two permitted levels of energy
ΔE = -
Let's apply these relationships our problem.
Let's start by knowing the energy of level n = 7
E₇ = - 13.606 / 7²
E₇ = - 0.27767 eV
Now let's see what the energy of the emitted photon
E = h f
c = λ f
f = c / λ
E = h c / λ
E = 6.63 10⁻³⁴ 3 10⁸/1005 10⁻⁹
E = 19,791 10⁻²⁰ J
Let's reduce to eV
E = 19,791 10⁻²⁰ (1 eV / 1.6 10⁻¹⁹)
E = 1,237 eV
The possible transitions from this level are towards n = 6, 5, 4,3,2, 1
We must test the different values until we find the right one
Energy of the states
n
6 -0.378
5 -0.544
4 -0.850
3 -1,512
2 -3,402
1 -13,606
Let's examine the transition n = 7 to n = 6
ΔE = - 0.27767 - (-0.3779)
ΔE = 0.10023 eV
n = 7 to n = 5
ΔE = -0.27767 - (-0.5442)
ΔE = 0.267 eV
n = 7 a n = 4
ΔE = -0.27767- (-0.8504)
ΔE = 0.573 eV
n = 7 a n = 3
ΔE = -0.27767 - (- 1.5118)
ΔE = 1.234 Ev
This is the transition sought, so that the electron goes from level n = 7 to level n = 3