With speeds up to 90 miles per hour, what is the fastest sport on ice?.

During the period of adolescence, which is generally between 13-19, the individual goes through a transitional period which is characterized by changes in emotional, physical and mental capacities.

These changes consequently result in the adolescents' desire to be more independent, and to govern their lives as how they deem more fitting, which results in the rebellious nature in the individual.

The other options include characteristics that MAY be seen in individuals, but is not a defining characteristic of adolescence and is not very common.

Hope this helps.

7 0

3 years ago

Determine the minimum angle at which a roadbedshould be banked

poizon [28]

To solve this problem, apply the concepts related to the relationship given between the centripetal Force and the Weight.

The horizontal force component is equivalent to the weight of the car, while the vertical component is linked to the centripetal force exerted on the car, therefore,

$T cos\theta = mg \rightarrow T = \frac{mg}{cos\theta}$

$Tsin\theta = \frac{mv^2}{r} \rightarrow T = \frac{mv^2/r}{sin\theta}$

Equating both equation we have that,

$\frac{mv^2}{r} = mgtan\theta$

$tan\theta = \frac{v^2}{rg}$

Rearranging to find the angle we have that,

$\theta = tan^{-1} (\frac{v^2}{rg})$

Our values are given as,

$r = 2.00*10^2m$

$v = 20m/s$

$\theta = tan^{-1}(\frac{20^2}{(2*10^{2})(9.8)})$

$\theta = 11.53 \°$

Therefore the minimum angle will be 11.53°

5 0

3 years ago

Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential

mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0

3 years ago