Answer:
a). The velocity of the first log is -1.65 m/s.
(b). The velocity of the second log is 1.07 m/s.
Explanation:
Given that,
Mass of lumberjack M= 110 kg
Mass of log m= 206 kg
Final velocity = 3.09 m/s
(a). We need to calculate the velocity of the first log just before the lumberjack jumps off
Using conservation of momentum

Put the value into the formula



The velocity of the first log is -1.65 m/s.
(b). If the lumberjack comes to rest relative to the second log
We need to calculate the velocity of the second log


Put the value into the formula


The velocity of the second log is 1.07 m/s.
Hence, (a). The velocity of the first log is -1.65 m/s.
(b). The velocity of the second log is 1.07 m/s.