To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.
Mathematically the expression is given as
Where,
= Initial Intensity
I = Final Intensity after pass through the polarizer
= Angle between the polarizer and the light
Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as
Using the Malus Law we have,
Angle with respect to maximum is 
Answer:
my method is guessing it works 50% of the time :)
Explanation:
Answer:
q = 4.87 X 10^ -14 C
Explanation:
As d=0.350 mm
The ink drop will be accelerated by the electric field between the plates:
a = F/m
d = a(D0 / v)^2 / 2 ...... 1
a = qE/m ............... 2
Substituting 2 into 1:
d = (qE/m)(D0 / v)^2 / 2
q = 2mdv^2 / [E(D0)^2]
q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]
q = 4.87e-14 C
Answer:
d.20760 J
Explanation:
We are given that
Mass of cart=m=100 kg
At the top,h=22 m
Amount of energy convert into heat due to friction=E=800 J
We have to find the kinetic energy at the bottom of the ramp.
Potential energy drop=mgh=
Kinetic energy at the bottom=Potential energy drop-energy lost due to friction
Kinetic energy at the bottom =(21560-800) J
Kinetic energy at the bottom=20760 J
Hence, the kinetic energy at the bottom of the ramp=20760 J
d.20760 J
