Question

A pilot wishes to fly on a course of 290° with an air speed of 300 knots when the wind blows from 224° at 18 knots. Find the drift angle to the nearest hundredth of a degree.
a) 3.18 degrees
b) 5.07 degrees
c) 86.82 degrees
The answer is 3.18 degrees.

Answer 1

Answer:

a) 3.18 degree.

Explanation:

tan Ф =  v sinα /( u + v cos α )

v is velocity of the air , u is velocity of pilot , α is angle between u and v and Ф is drift angle of the pilot

tan Ф = 18 sin ( 290 - 224) / 300 + 18 cos ( 290 - 224 )

           = 18 sin 66 / ( 300 + 18 cos 66)

             = 18 x .91 / (300 + 18 x .40)

               = 16.38 / 305.4 = .0536

       Ф = 3 .18 degree.

Answer 2

The answer is 3.18 degrees