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2 years ago

13

Not homework BUT

1 answer:

Alborosie2 years ago

5 0

Answer:

242 days

Step-by-step explanation:

1081-597=484

it is increasing by 2wins every day so 484/2=242 days

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What is the result of isolating x^2 in the equation below 10x^2-36y^2=100

aniked [119]

For the answer to the question above,
<span>10x^2-36y^2=100
Then isolate x^2, first add 36y^2 to both sides: 10x^2 = 100 + 36y^2 divide both sides by 10:
x^2 = 10 + 3.6y^2 or
10 + 36/10 * y^2 = 10 + 18/5 * y^2
</span>
So the answer to this question is
<span><span>x2</span>=10 + (<span>18/5)</span><span>y2

I hope my answer helped you. Have a nice day!</span></span>

5 0

3 years ago

Read 2 more answers

Graph the solution to y< = 1/5x+2

faust18 [17]

Answer:

FDFDD

Step-by-step explanation:

5 0

3 years ago

If sec ⁡ θ = − 2 secθ=−2 and the reference angle of θ θ is 6 0 ∘ 60 ∘ , find both angles in degrees from 0 ∘ ≤ θ < 36 0 ∘ 0 ∘

jek_recluse [69]

Yoasuibcerknvsekkvdh

4 0

3 years ago

What is the product?

fredd [130]

Answer:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

Step-by-step explanation:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4 can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace 4k +2 by 2 (2k + 1)

and

k² - 4 by (k-2)(k+2) in the expression given

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

$\frac{2(2k+ 1)}{(k-2)(k+2)}$ × $\frac{k-2}{2k+1}$

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;

$\frac{2}{k + 2}$

Therefore, $\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

3 0

3 years ago

Read 2 more answers

432566 10.5.623467.14,5<br><br> 4. What is the 1s (lower) quartile of the data set?

egoroff_w [7]

Answer:

I feel sorry that looks hard. see how do you like it. waiting for an answer and then someone finally answers. and there being a smart Butt

Step-by-step explanation:

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3 years ago