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Nataliya [291]
3 years ago
11

If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring

Physics
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

1 N

Explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

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The correct answer is the statement #3. The statement that says: your hypothesis must be testable, is a true statement about the scientific process. IT will be truly unreasonable and a waste to be doing experiments on a hypothesis that is not even possible to solve.
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A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?
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The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

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ω = 2π x (5.25 / 3)

ω =  11 rad/s

<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

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where;

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Learn more about tangential velocity here: brainly.com/question/25780931

4 0
3 years ago
The positive terminal of a voltage source (V=12V ) is connected to a capacitor C1 = 4 μF. This capacitor is then connected to a
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Answer: 16 μC

Explanation: In order to solve this problem we have to reduce to the equivalent capacitor for the initial conection:

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1. refers to all liquid fresh water located above ground.
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Answer:

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