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Elena L [17]
3 years ago
12

The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall buildin

g, about how fast will it be falling after 3 seconds?
Physics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Given Information:  

Acceleration of gravity = g = 9.8 m/s²

Time period = t = 3 seconds

Required Information:

velocity = v = ?

Answer:  

v = 29.4 m/s

Explanation:  

As we know the velocity of an object under free fall assuming that the object was initially at rest is given by

v = -gt

Where minus sign indicates that the object is moving downward

v = -9.8*3

v = -29.4 m/s

Therefore, the rock will be falling at the speed of 29.4 m/s after 3 seconds.

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Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat
vichka [17]
The period of a pendulum is given by
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
\frac{T_m}{T_e} =  \frac{2 \pi  \sqrt{ \frac{L}{g_m} } }{2 \pi  \sqrt{ \frac{L}{g_e} } }=    \sqrt{ \frac{g_e}{g_m} }
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is g_e = 9.81 m/s^2 while on the Moon is g_m=1.63 m/s^2, the ratio between the period on the Moon and on Earth is
\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45

3 0
3 years ago
Please help! This is due in 10 minutes
Elenna [48]

Answer:

Atom - the basic particle of matter

Density - calculated from measurements of mass and volume

Motion - calculated from measurements of distance and time

Energy - can change form and move matter

Matter - the scientific word for <em>stuff</em>

<em />

Hope this helps! Please mark brainliest if correct :D

8 0
3 years ago
If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas
blagie [28]

Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

Option A is correct. (The faster object encounters more resistance)

Air resistance depends on various factors:

  • Speed of the object
  • Cross-sectional area of the object
  • Shape of the object

Formula:

F=\frac{1}{2}C_d\rho A v^{2}

As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.

6 0
3 years ago
The objects listed are placed at the top of a ramp and roll down to the bottom without slipping. Assuming that there is no air r
Thepotemich [5.8K]

Explanation:

For each object, the initial potential energy is converted to rotational energy and translational energy:

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For the marble (a solid sphere), I = ⅖ mr².

For the basketball (a hollow sphere), I = ⅔ mr².

For the manhole cover (a solid cylinder), I = ½ mr².

For the wedding ring (a hollow cylinder), I = mr².

If we say k is the coefficient in each case:

mgh = ½ (kmr²) ω² + ½ mv²

For rolling without slipping, ωr = v:

mgh = ½ kmv² + ½ mv²

gh = ½ kv² + ½ v²

2gh = (k + 1) v²

v² = 2gh / (k + 1)

The smaller the value of k, the higher the velocity.  Therefore:

marble > manhole cover > basketball > wedding ring

7 0
4 years ago
What is capital of Thaivan?
lisabon 2012 [21]

are you sure it's Thaivan or Taiwan. If it's Taiwan than it's Taipei.

    Hope this help :))

4 0
3 years ago
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