B, the inverse is not a function, because to the x-value 0 the inverse relation orders two values: the 1 and the 5 as well.
Answer:
The answer is 25.
Step-by-step explanation:
Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
Answer:
50%
Step-by-step explanation:
half of the numbers on dice are even
Answer:
Step-by-step explanation:
By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that
f'(c) = [f(6) - f(1)]/ (6 - 1)
So, f(6) - f(1) = 5f'(c).
Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20
So, f(6) - f(1) is between 10 and 20.
