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rodikova [14]
2 years ago
11

Which of the following situations indicates an alpha emission?

Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
4 0
Your answer would be C. Alpha decay involves the ejection of 2 protons and 2 neutrons from the nucleus for a total of 4 amu lost. This form of decay is most common in heavy elements.
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Put these different types of radiation in order from MOST to LEAST penetrating.
Naily [24]

Answer:

C. Gamma > beta > alpha

Explanation:

<u>Alpha rays</u> : These are positively charged  and have mass 4u. These contain high energy Helium nucleus with 2 proton and 2 neutron.

These are heavier and maximum charged than beta and gamma particles.They have low velocity,least penetration power (can't travel more than 10-18 cm).

<u>Beta rays</u> : They are negatively charged and have negligible mass.

On emmission of beta particle, neutron is divided into proton and electron. They have less mass and very high velocity, so their penetrating power is more than alpha particles.

<u>Gamma rays</u>: These are parts of electromagnetic spectrum and travel with the speed of light (maximum velocity).Gamma rays do not have mass have maximum penetrating power.

4 0
2 years ago
If you were asked to convert 25 cg to the unit hg, which of the following would be the first fraction used in the conversion? on
zhannawk [14.2K]
We are asked to convert 25 cg to units of hg.

1 cg = 1 centigram = 10⁻² g
1 hg = 1 hectogram = 10² g

The options given are:

a) 1 hg/ 10² g
b) 10² cg/ 1 hg
c) 10² hg/ 1 cg
d) 10⁻² g/ 1 cg

To convert 25 cg to 1 hg, we could convert the 25 cg to grams first, then grams to hg.

25 cg · 10⁻² g/ 1cg = 0.25 g

Here we have converted our number from cg to grams. We can use another conversion of grams to hg to complete the conversion.

0.25 g · 1 hg/ 10² g = 0.0025 hg

Therefore, the first conversion we used was d) 10⁻² g/ 1 cg.
4 0
3 years ago
The antibiotic prontosil, developed by bayer pharmaceuticals in 1932, was used in saving the life of president roosevelt's son f
Alja [10]

Prontosil is a compound produced by the coupled reaction of an aryldiazonium ion and an aromatic compound.

<h3>What are diazonium compounds?</h3>

These are organic compounds in which there are ionic interactions between the azo group (-N₂⁺) and an anion X⁻.

The general structure is RN₂⁺X⁻.

  • R is the lateral chain that might be an aromatic ring, among other options.
  • N₂⁺ is the azo group
  • X⁻ is the anion

The azo group characterizes as being unstable and reactive. This property is because one of the N atoms has a positive charge.

-N⁺≡ N

<h3>What is the coupling reaction of aryldiazonium compounds?</h3>

Aryldiazonium salt reactions can occur in two ways,

  • Substitution reactions
  • Coupling reactions

Coupling reactions are the aromatic electrophilic substitution, where the aryldiazonium ion acts as an electrophile for an activated aromatic compound to attack it.

The coupling reaction occurs at the azo group level.

In the exposed example,

  • the benzene ring with sulfur bonded to oxygen atoms is the coupling component
  • the benzene ring with NH₂ and the azo group is the diazonium ion

In the attached files you will find the drawings.

You can learn more about diazonium compounds at

brainly.com/question/9061271

brainly.com/question/9389852

brainly.com/question/13147442

5 0
2 years ago
How many pencils are in 20 OWLS
AVprozaik [17]
Owls means a mammalian species
It is incorrect question
4 0
3 years ago
Read 2 more answers
What is the molar solubility of agcl in 0. 30 m nacl at 25°C. ksp for agcl is 1. 77 × 10^-10.
Rzqust [24]

Molar solubility of AgCl will be  0.59 ×  10^{-10} M.

The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.

A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.

Calculation of molar solubility:

Given data:

M = 0.30 M

K_{sp} = 1.77 × 10^{-10}

The reaction can be written as:

AgCl ⇔ Ag^{+} + Cl^{-}

s            s         (s+0.30)

K_{sp}  = [Ag^{+} ]+ [Cl^{-}]

1.77 × 10^{-10} = s (0.30)

s = 1.77 × 10^{-10}  / 0.3

s = 0.59 ×  10^{-10} M

Therefore, molar solubility of AgCl will be  0.59 ×  10^{-10} M.

To know more about molar solubility

brainly.com/question/16243859

#SPJ4

3 0
1 year ago
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