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Misha Larkins [42]
2 years ago
14

A chemist prepares a solution of copper) sulfate (cuso4)by weighing out 29.9 g of copper ) sulfate into a 150 into a 150.mLvolum

etric flask and filling the flask to the mark with water.
Chemistry
1 answer:
Alexxandr [17]2 years ago
6 0

Lol Most people would say c but its A

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What are the very reactive gasses of the periodic table called
kipiarov [429]

the very reactive gasses of the periodic table are called halogens.

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4 years ago
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Consider the following molecule.<br> 1. How many bonding pair of electrons are present?
Artemon [7]

Answer:

There are 3 bonding pairs of electrons

Explanation:

For every bond there is one bonded pair of electrons. NH₃ has three N-H bonds, so has three bonding pairs of electrons along with a lone pair of electrons

5 0
3 years ago
Phosphorus has three electrons in its 3p sublevel and sulfur has four. Phosphorus should have the lower ionization energy but it
Nadya [2.5K]

Answer:

B

Explanation:

First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.

8 0
3 years ago
A student creates a solution by dissolving some Na2SO4 (molar mass = 142.05 g/mol) in enough water to create 0.500 L of solution
NeX [460]

Answer : The mass of Na_2SO_4 is, 4.43 grams.

Explanation :

As we know that, when Na_2SO_4 dissolve in water then it dissociates to give 2 mole of sodium ion Na^+ and 1 mole of sulfate ion SO_4^{2-}

The chemical reaction will be:

Na_2SO_4\rightarrow 2Na^++SO_4^{2-}

Thus, the concentration of Na_2SO_4 = \frac{\text{Concentration of }Na^+}{2}=\frac{0.125M}{2}=0.0625M

First we have to calculate the moles of Na_2SO_4

\text{Concentration of }Na_2SO_4=\frac{\text{Moles of }Na_2SO_4}{\text{Volume of solution}}

0.0625M=\frac{\text{Moles of }Na_2SO_4}{0.500L}

\text{Moles of }Na_2SO_4=0.0312mol

Now we have to calculate the mass of Na_2SO_4

\text{Mass of }Na_2SO_4=\text{Moles of }Na_2SO_4\times \text{Molar mass of }Na_2SO_4

Molar mass of Na_2SO_4 = 142 g/mol

\text{Mass of }Na_2SO_4=0.0312mol\times 142g/mol=4.43g

Thus, the mass of Na_2SO_4 is, 4.43 grams.

6 0
3 years ago
What is The maximum amount of a substance that can be dissolved by another substance
Oksanka [162]

Solubility varies vastly. It depends on the solute, solvent, temperature, and pressure.

6 0
3 years ago
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