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Misha Larkins [42]
2 years ago
14

A chemist prepares a solution of copper) sulfate (cuso4)by weighing out 29.9 g of copper ) sulfate into a 150 into a 150.mLvolum

etric flask and filling the flask to the mark with water.
Chemistry
1 answer:
Alexxandr [17]2 years ago
6 0

Lol Most people would say c but its A

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How many moles of solute would be dissolved in .500 kg of solvent to make a 2.50 molal NaOH solution?
Tom [10]

Molality is a measure of concentration that relates the moles of solute to the kilograms of solvent, it is described by the following equation:

Molality=\frac{molSolute}{kgSolvent}

We are given the molality(2.50m) and kilograms of solvent(0.500kg), so we solve for moles of solute from the equation:

molSolute=Molality\times kgSolvent\begin{gathered} molSolute=2.50m\times0.500kg \\ molSolute=1.25molSolute \end{gathered}

To make a 2.50molal NaOH solution would be needed 1.25moles of solute

Answer: 1.25 moles

3 0
1 year ago
How is the melting point of a substance recorded
GrogVix [38]

1. slowly heat stubstance.

2. once the substance is at the most liqued state take the temp. that's the melting point of that subtance.

hope that helps, any other questions feel free to DM me dont wate your points. :)

6 0
2 years ago
Which term refers to the smallest particle of a compound with all the properties of that compound?
Svetradugi [14.3K]

Answer:

molecule. The smallest part of a compound is the molecule. A molecule retains all the properties of that compound.

Explanation:

thanks me later

4 0
2 years ago
Read 2 more answers
Calculate the food energy (joules/
Anna007 [38]

Calculate the food energy (joules/g) of one of your food samples. one chemistry calorie is equal to 4.186 joules. convert the energy you calculated to kilojoules (1 kj = 1000 j). since nothing is given, an example is avocadoes have 160 cal/100 g serving

(160 cal/ 100 g)(4.186 J/ 1 cal) (1 kJ/1000 J) = 0.0067 kJ/g

5 0
3 years ago
A gas sample is held at constant temperature. What happens to the pressure of the sample if the volume is doubled and the number
Iteru [2.4K]

Answer:

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

Explanation:

Step 1: Data given

Temperature = constant

Volume will be doubled

Number of molecules will be doubles

Step 2:

p*V = n*R*T

⇒ gas constant and temperature are constant

Initial pressure = n*R*T / V

Initial pressure = 2*R*T/2

Initial pressure =  RT

Final pressure = 4*RT / 4

Final pressure = R*T

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

3 0
2 years ago
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