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Tresset [83]
3 years ago
10

A person weighing 504 Newtons enters an elevator and stands on a scale which reads his weight in Newtons. The elevator starts to

accelerate upward at a rate of 8.53 m/s^2. What does the scale read while the elevator is accelerating upward? (Use g = 9.80 m/s^2)
Physics
1 answer:
Tomtit [17]3 years ago
4 0

Answer:

942.68 N

Explanation:

Weight of man = 504 N = W

a = Acceleration = 8.53 m/s²

g = Acceleration due to gravity = 9.80 m/s²

Mass of man

m=\frac{W}{g}=\frac{504}{9.8}

Weight shown when elevator is being accelerated

W_n=ma+mg\\\Rightarrow W_n=\frac{504}{9.8}\times 8.53+504\\\Rightarrow W_n=942.68\ N

Scale reading while the elevator is accelerating upward is 942.68 N.

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Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average
ryzh [129]

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9517.2 lbm

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7 0
4 years ago
In this circuit the battery provides 3 V, the resistance R1 is 7 Ω, and R2 is 5 Ω. What is the current through resistor R2? Give
sveta [45]

Answer:

The current pass the R_2 is  I  = 0.25 A

Explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

    The voltage  is  V =  3V

     The first resistance is  R_1 = 7 \Omega

     The second resistance is  R_2 = 5 \Omega

Since the resistors are connected in series their equivalent resistance is  

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Substituting values

         R_{eq} = 7 + 5

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Since the resistance are connected in serie the current passing through the circuit  is the same current passing through R_2 which is mathematically evaluated as

        I  =  \frac{V}{R_{eq}}

Substituting values  

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3 0
4 years ago
I need help ! if anyone answers this its worth 40 points please help !!
Sliva [168]
Double displacement...I think
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3 years ago
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