Which of the following requires formwork?
1 answer:
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Answer:
/****************** The code for a form application that uses radioButtons * *and displays new form based on the user selection *****************/
Using system;
Using system windows forms;
namespace CarDealer
{
Public partial class Form1 : Form
{
public Form1()
{
//default constructor to initialize components
InitializeComponent();
}
//when user clicks on the details button
private void detail_Click
(Object sender, EventArgs e)
{
if (model1,Checked)
{
Forms2 f = new Form2()
f.ShowDialog()
model1.Checked = false
}
if (model2.Checked)
{
Form3 f = new Form3();
f.ShowDialog();
model2.Checked = false;
}
if (model3.Checked)
{
Form4 f = new Form4();
f.ShowDialog();
model3.Checked = false;
}
}
}
}
Explanation:
Program plan
- Design form: Place label controls with text as select car model and one empty label control to display total price. Change front type and size from each other labels properties window.
- Add three radio buttons with text Renault Kwit, Tata Tiago, Mahindra KUV 100.
- Add button with text View Details.
- Add 3 new windows form from project menu for each car model.
- Change form name and respective car models.
- Place picturebox control to each form by using image property add .jpeg image and place label control containing price of each model to each form
- When user select car model and click on view details, new form containing car model details is displayed.
Form Design is attached below
Maximum absolute values of the shear = 28 KN
Maximum absolute values of bending moment = 5.7 KN.m
<h3>How to draw Shear Force and Bending Moment Diagram?</h3>A) We can see the beam loaded in the first image attached.
For the shear diagram, let us calculate the shear from point load to point load.
From A to C, summing vertical to zero gives; ∑fy = 0: -20 - V = 0
V = -20 KN
From C to D, summing vertical to zero gives; ∑fy = 0: -20 + 48 - V = 0
V = 28 KN
From D to E, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - V = 0
V = 8 KN
From E to B, summing vertical to zero gives; ∑fy = 0: -20 + 48 - 20 - 20 - V = 0
V = -12 KN
For the bending moment diagram, let us calculate the bending moment from point load to point load.
At point A, the bending moment would be zero. Thus, M_A = 0 KN.m
At point C, taking moment about point C and equating to zero gives;
M_C = 0. Thus; 20(0.225) + M = 0
M = -4.5 KN.m
At point D, taking moment about point D and equating to zero gives;
M_D = 0. Thus; 20(0.525) - 48(0.3) + M = 0
M = 3.9 KN.m
At point E, taking moment about point E and equating to zero gives;
M_D = 0. Thus; 20(0.75) - 48(0.525) + 20(0.225) + M = 0
M = 5.7 KN.m
At point B, taking moment about point E and equating to zero gives;
M_E = 0. Thus; 20(1.05) - 48(0.825) + 20(0.525) + (20 * 0.3) + M = 0
M = 2.1 KN.m
2) From the attached diagrams, we can deduce that;
Maximum absolute values of the shear = 28 KN
Maximum absolute values of bending moment = 5.7 KN.m
Read more about shear force & bending moment diagram at; brainly.com/question/14834487
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