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2 years ago

1. Band saw lower wheel does not require a guard *

Engineering

1 answer:

soldi70 [24.7K]2 years ago

8 0

Answer:

1. false

2. true

3. true

Explanation:

thats all hope I help let me know if you need something eles

branliest pls

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El protozoos es del reino protista?

iogann1982 [59]

Answer: Si (Yes)

Explanation:

3 0

3 years ago

Read 2 more answers

A flow of 12 m/s passes through a 6 m wide, 2 m deep rectangular channel with a bed slope of 0. 001. If the mean velocity of flo

prohojiy [21]

Answer:

manning's coefficient is 0.0357

Explanation:

Given:

Velocity of flow, v = 12 m/s

Width of the channel, b = 6 m

Depth of the channel, d = 2 m

bed slope, s = 0.001

mean velocity of flow, V = 1 m/s

now, the velocity is given as:

$V= \frac{1}{n}R^{\frac{2}{3}}S^{\frac{1}{2}}$

where,

n is the manning's coefficient

R is hydraulic mean depth

R = (Area of the channel) / (wetted Perimeter of the channel)

now,

R = (2 × 6) / ((2 × 2) + 6)

R = 12 / 10 = 1.2 m

now, on substituting the values in the equation for velocity, we get

$1= \frac{1}{n}1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}$

$n= 1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}$

n = 0.0357

hence, the value of manning's coefficient is 0.0357

8 0

3 years ago

Write a Nested While Loop that will increment the '*' from 1 to 10.

andrey2020 [161]

Answer:

The program is as follows:

i = 1

while(i<11):

j = 1

while(j<=i):

print('*', end = '')

j += 1

i += 1

print()

Explanation:

Initialize i to 1

i = 1

The outer loop is repeated as long as i is less than 11

while(i<11):

Initialize j to 1

j = 1

The inner loop is repeated as long as j is less than or equal i

while(j<=i):

This prints a *

print('*', end = '')

This increments j and ends the inner loop

j += 1

This increments i

i += 1

This prints a blank and ends the inner loop

print()

8 0

3 years ago

What is code in Arduino to turn led on and off

11Alexandr11 [23.1K]

here's your answer..

4 0

3 years ago

What is the maximal coefficient of performance of a refrigerator which cools down 10 kg of water (and then ice) to -6C. Upper he

inysia [295]

Given:

Temperature of water, $T_{1}$ = $-6^{\circ}C$ =273 +(-6) =267 K

Temperature surrounding refrigerator, $T_{2}$ = $21^{\circ}C$ =273 + 21 =294 K

Specific heat given for water, $C_{w}$ = 4.19 KJ/kg/K

Specific heat given for ice, $C_{ice}$ = 2.1 KJ/kg/K

Latent heat of fusion, $L_{fusion}$ = 335KJ/kg

Solution:

Coefficient of Performance (COP) for refrigerator is given by:

Max $COP_{refrigerator}$ = $\frac{T_{2}}{T_{2} - T_{1}}$

= $\frac{267}{294 - 267}$ = 9.89

Coefficient of Performance (COP) for heat pump is given by:

Max $COP_{heat pump}$ = $\frac{T_{1}}{T_{2} - T_{1}}$ $\frac{294}{294 - 267}$ = 10.89

6 0

3 years ago