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Ludmilka [50]
2 years ago
9

Peter does 3,000 joules (J) of work by moving an object 40 meters (m). What is the force that Peter applies to the object? A 75

N B 2,960 N C 3,040 N D 120,000 N
Physics
1 answer:
Papessa [141]2 years ago
4 0

The force that peter applies to the object of distance 40m is 75N.

<h3>HOW TO CALCULATE FORCE</h3>

The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;

Force = Work done ÷ distance

According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:

Force = 3000J ÷ 40m

Force = 75N

Therefore, the force that peter applies to the object of distance 40m is 75N.

Learn more about force at: brainly.com/question/26115859

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In places such as hospital operating rooms or factories for electronic circuit boards, electric sparks must be avoided. A person
FrozenT [24]

Time taken by the rubber-soled shoes to reduce a person's potential from 3.00×10³ V to 100V is 3.91s

The initial potential difference \Delta V_o is related to the final potential difference \Delta V by

\Delta V=\Delta V_{o} e^{-t / \tau}

Our target is to find t, so we rearrange equation (1) for t to be

\Delta V=\Delta V_{o} e^{-t / RC}\\ \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) = \frac{-t}{RC}\\ t= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \tag{2}

The body has a capacitance 150 pF while the foot has a capacitance 80 pF and both are in parallel connection. So, the equivalent capacitance is

C= 150 \mathrm{~pF} + 80 \mathrm{~pF} = 230 \mathrm{~pF}

The shoes of the rubber-soled has resistance R=5000 \mathrm{~M\Omega}. Plug the values for \Delta V, \Delta V_o and C into equation (2) to get the time t.

t&= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \\ &= -( 5000 \times 10^{6} \mathrm{~\Omega})(230 \times 10^{-12} \mathrm{~F}) \ln \left ( \frac{100\mathrm{~V}}{3000 \mathrm{~V}} \right ) \\ &= {3.91 \mathrm{~s}}

Learn more about capacitance here:

brainly.com/question/12644355

#SPJ4

3 0
2 years ago
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madreJ [45]

<u>Answer</u>

To know where it starts we look where the zero mark of the vernier scale starts. The make just before reaching where the zero mark is marks the value to use<em>. </em>


<u>Explanation</u>

A vernier caliper is an instrument that is used to measure the diameter of small circular objects such as diameter of a wires, thickness of an iron sheet.

The objects to be measured is place between the jaws of the calipers.

The vernier scale has two scales, the vernier scale and the main scale which is the very top scale.<em> To know where it starts we look where the zero mark of the vernier scale starts. The make just before reaching where the zero mark is marks the value to use. </em>

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<h3><u>Answer;</u></h3>

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