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3 years ago

There are some points on a standing

Physics

2 answers:

bija089 [108]3 years ago

7 0

Answer:

Nodes.

Explanation:

Nodes are a point that are on a standing wave that never move.

kipiarov [429]3 years ago

4 0

Answer:

C. Nodes

Explanation:

There are some points on a standing wave that never move. These points are called Nodes.

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20-point physics question! :D

Virty [35]

I think, it must be a chemical. Because the fire is a chemical reaction. So, the chemical energy converted to heat energy.

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3 years ago

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A planet's moon travels in an approximately circular orbit of radius 8.6 107 m with a period of 6 h 25 min. Calculate the mass o

DerKrebs [107]

Answer:

m v^2 / R = G M m / R^2 gravitational attraction = centripetal force

M = v^2 R / G solving for M

period = 6 h 25 min = (6 * 3600 + 25 * 60) sec = 23,100 sec = T

v = 2 pi R / T

M = 4 pi^2 R^3 / (G T^2)

M = 39.5 * (8.6E7)^3 / (6.67E-11 * 2.31E4^2)

M = 39.5 * 636 / (6.67 * 5.34) * 10^24

M = 7.05 * 10^26 kg

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3 years ago

Kingda Ka has a maximum speed of 57.2 m/s. Determine the height of the hill on this roller coaster. Explain to get full credit,

kodGreya [7K]

This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.

The height of the hill is "166.76 m".

<h3>LAW OF CONSERVATION OF ENERGY:</h3>

According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:

$Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\
\frac{1}{2}mv_{max}^2=mgh\\\\
h=\frac{v_{max}^2}{2g}$

where,

h = height of the hill = ?

$v_{max}$ = maximum velocity = 57.2 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$h=\frac{(57.2\ m/s)^2}{2(9.81\ m/s^2)}\\\\
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Learn more about the law of conservation of energy here:

brainly.com/question/101125

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3 years ago

A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.

Ivanshal [37]

Part 1)

here we know that supply took 10 s to reach the ground

so here we will have

$y = \frac{1}{2}gt^2$

$y = \frac{1}{2}\times 9.8 \times 10^2$

$y = \frac{1}{2}\times 9.8 \times 100$

$y = 490 m$

Part 2)

Here all the supply covered horizontal distance of 650 m in 10 s interval of time

so here we can say

$speed = \frac{distance}{time}$

$v = \frac{650}{10}$

$v = 65 m/s$

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3 years ago

ANSWER FOR BRAINLIEST

Vedmedyk [2.9K]

I think the answer is A

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3 years ago